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Mathematics 0580 · Chapter 6

Trigonometry

Pythagoras' theorem, sine, cosine and tangent in right-angled triangles, and the sine rule, cosine rule and area rule for any triangle.

Written for the 2025–2027 syllabus · 7 min read

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Pythagoras' theorem

A right-angled triangle whose two shorter sides are both 3 cm and whose hypotenuse is marked with a question mark

A right-angled triangle whose two shorter sides are both 3 cm and whose hypotenuse is marked with a question mark

32+32=c2⇒c=18=4.2 cm3^2 + 3^2 = c^2 \quad\Rightarrow\quad c = \sqrt{18} = 4.2\text{ cm}

Right-angled triangles

For an angle θ\theta in a right-angled triangle: the hypotenuse is the longest side, the opposite side is the side facing θ\theta, and the adjacent side is the side next to θ\theta (that is not the hypotenuse).

RatioFormula
Sinsin⁡(θ)=oppositehypotenuse\sin(\theta) = \dfrac{\text{opposite}}{\text{hypotenuse}}
Coscos⁡(θ)=adjacenthypotenuse\cos(\theta) = \dfrac{\text{adjacent}}{\text{hypotenuse}}
Tantan⁡(θ)=oppositeadjacent\tan(\theta) = \dfrac{\text{opposite}}{\text{adjacent}}

A right-angled triangle with the vertical side 3 cm, the hypotenuse 5 cm, and the angle theta marked at the bottom right

A right-angled triangle with the vertical side 3 cm, the hypotenuse 5 cm, and the angle theta marked at the bottom right

Since we have the lengths of the opposite side and the hypotenuse, we use sin:

sin⁡(θ)=35⇒θ=sin⁡−1(35)=36.9∘\sin(\theta) = \frac{3}{5} \quad\Rightarrow\quad \theta = \sin^{-1}\left(\frac{3}{5}\right) = 36.9^\circ

The shortest distance from a point to a line is the perpendicular distance.

A line at 30 degrees to a horizontal line, 5 cm long, from the horizontal line up to a point, with the perpendicular distance marked with a question mark

A line at 30 degrees to a horizontal line, 5 cm long, from the horizontal line up to a point, with the perpendicular distance marked with a question mark

Since the shortest distance is the perpendicular distance, we calculate the side opposite the angle using sine:

sin⁡(30∘)=x5⇒x=5sin⁡(30∘)=2.5 cm\sin(30^\circ) = \frac{x}{5} \quad\Rightarrow\quad x = 5\sin(30^\circ) = 2.5\text{ cm}

tan⁡(θ)=14⇒θ=tan⁡−1(14)=14.0∘\tan(\theta) = \frac{1}{4} \quad\Rightarrow\quad \theta = \tan^{-1}\left(\frac{1}{4}\right) = 14.0^\circ

Write the answer to 1 decimal place even if it is .0.0.

Non-right-angled triangles

Sine rule

A triangle with a 40 degree angle at the left, the side opposite it 4 cm, and the side next to it 2 cm with the angle A at the far end

A triangle with a 40 degree angle at the left, the side opposite it 4 cm, and the side next to it 2 cm with the angle A at the far end

The 4 cm side is opposite the 40∘40^\circ angle, and the 2 cm side is opposite AA:

4sin⁡40∘=2sin⁡A⇒sin⁡A=2sin⁡40∘4⇒A=18.7∘\frac{4}{\sin 40^\circ} = \frac{2}{\sin A} \quad\Rightarrow\quad \sin A = \frac{2\sin 40^\circ}{4} \quad\Rightarrow\quad A = 18.7^\circ

Cosine rule

Use the cosine rule when you know:

  • all three sides (SSS), or
  • two sides and the angle between them (SAS).

A triangle with two sides 5 cm and 3 cm meeting at an 80 degree angle, and the third side labelled A

A triangle with two sides 5 cm and 3 cm meeting at an 80 degree angle, and the third side labelled A

A2=52+32−2(5)(3)cos⁡(80∘)=34−30cos⁡80∘A^2 = 5^2 + 3^2 - 2(5)(3)\cos(80^\circ) = 34 - 30\cos 80^\circ

A=5.37 cmA = 5.37\text{ cm}

Area rule

Use it when you know two sides and the angle between them (SAS).

A triangle with two sides 5 cm and 3 cm meeting at an 80 degree angle

A triangle with two sides 5 cm and 3 cm meeting at an 80 degree angle

Area=12(5)(3)sin⁡80∘=7.4 cm2\text{Area} = \tfrac{1}{2}(5)(3)\sin 80^\circ = 7.4\ \text{cm}^2

Exact trigonometric values

You must know these values without a calculator:

xx0∘0^\circ30∘30^\circ45∘45^\circ60∘60^\circ90∘90^\circ
sin⁡x\sin x0012\dfrac{1}{2}22\dfrac{\sqrt{2}}{2}32\dfrac{\sqrt{3}}{2}11
cos⁡x\cos x1132\dfrac{\sqrt{3}}{2}22\dfrac{\sqrt{2}}{2}12\dfrac{1}{2}00
tan⁡x\tan x0033\dfrac{\sqrt{3}}{3}113\sqrt{3}not defined

Trigonometric functions

The graphs, for 0∘≤x≤360∘0^\circ \le x \le 360^\circ

  • y=sin⁡xy = \sin x starts at 0, rises to a maximum of 1 at 90∘90^\circ, is 0 at 180∘180^\circ, falls to −1-1 at 270∘270^\circ and is 0 at 360∘360^\circ.
  • y=cos⁡xy = \cos x starts at 1, is 0 at 90∘90^\circ, is −1-1 at 180∘180^\circ, 0 at 270∘270^\circ and 1 at 360∘360^\circ. It is the sine graph shifted 90∘90^\circ to the left.
  • y=tan⁡xy = \tan x is 0 at 0∘0^\circ, 180∘180^\circ and 360∘360^\circ, rises steeply towards 90∘90^\circ and 270∘270^\circ, where it is undefined (the graph has asymptotes).

Sine and cosine repeat every 360∘360^\circ and stay between −1-1 and 11. Tangent repeats every 180∘180^\circ.

Solving trigonometric equations

A calculator gives one answer. Use the graph's symmetry to find the other one in 0∘≤x≤360∘0^\circ \le x \le 360^\circ.

Equation typeSecond solution
sin⁡x=k\sin x = k180∘−x180^\circ - x
cos⁡x=k\cos x = k360∘−x360^\circ - x
tan⁡x=k\tan x = k180∘+x180^\circ + x
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