Physics (AS & A Level) · May / June 2018 · Paper 23 · Question 7
9702
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A graph of nucleon number A against proton number Z is shown in Fig. 7.1. 20980 81 82 83 84 85 86 87 88 210 211 212 213 214 215 216 217 218 219 A Z P Fig. 7.1 The graph shows a cross (labelled P) that represents a nucleus P. Nucleus P decays by emitting an α particle to form a nucleus Q. Nucleus Q then decays by emitting a β– particle to form a nucleus R.
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7(a)(i)[1]
7(a)(ii)[1]
7(b)[1]
7(c)[1]
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