Physics (AS & A Level) · May / June 2018 · Paper 23 · Question 6
9702
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A wire X has a constant resistance per unit length of 3.0 Ω m–1 and a diameter of 0.48 mm.
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6(a)[3]
6(b)(i)[1]
6(b)(ii)[4]
1. current in resistor = 1.8 / 4.5 (= 0.40 A) current in wire = 1.6 – 0.40 (= 1.2 A) RX = 1.8 / 1.2 = 1.5 Ω or RT = 1.8 / 1.6 or (5.0 / 1.6) – 2.0 (= 1.125 Ω) (C1) (1 / 1.125) = (1 / 4.5) + (1 / RX) (C1) RX = 1.5 Ω (A1) 2. length = 1.5 / 3.0 or 1.5 × 1.8 × 10–7 / (5.4 × 10–7) = 0.50 m Mark
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