Physics (AS & A Level) · May / June 2016 · Paper 23 · Question 5
9702
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5(a)[2]
the total momentum of a system (of colliding particles) remains constant provided there is no resultant external force acting on the system/ isolated or closed system [2]
5(b)(i)[1]
the total kinetic energy before (the collision) is equal to the total kinetic energy after (the collision) [1]
5(b)(ii)[1]
p (= mv = 1.67 × 10–27 × 500) = 8.4 (8.35) × 10–25 N s [1]
5(b)(iii)[2]
1. mvA cos 60° + mvB cos 30° or m(vA 2 + vB 2) 1/2 2. mvA sin 60° + mvB sin 30° [2]
5(b)(iv)[3]
8.35 × 10–25 or 500m = mvA cos 60° + mvB cos 30° and 0 = mvA sin 60° + mvB sin 30° or using a vector triangle vA = 250 m s–1 vB = 430 (433) m s–1 [3]
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