Physics (AS & A Level) · May / June 2016 · Paper 23 · Question 4
9702
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A spring balance is used to weigh a cylinder that is immersed in oil, as shown in Fig. 4.1. spring balance 5.0 cm thin wire cross-sectional area 13 cm2 cylinder oil Fig. 4.1 The reading on the spring balance is 4.8 N. The length of the cylinder is 5.0 cm and the cross- sectional area of the cylinder is 13 cm2. The weight of the cylinder is 5.3 N.
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4(a)[1]
(resultant force = 0) (equilibrium) therefore: weight – upthrust = force from thin wire (allow tension in wire) or 5.3 (N) – upthrust = 4.8 (N) [1]
4(b)[3]
difference in weight = upthrust or upthrust = 0.5 (N) 0.5 = ρghA or m = 0.5 / 9.81 and V = 5.0 × 13 × 10–6 (m3) ρ = 0.5 / (9.81 × 5.0 × 13 × 10–6) = 780 (784) kg m–3 [3]
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