Mathematics · Oct / Nov 2025 · Paper 51 · Question 6
YMA01
As printed in the paper
The question as text
6. v ms–1 30 0 0 10 30 35 t s Figure 4 The point O lies on a straight horizontal road. At time t = 0, a car leaves O and travels along the road. –1, of the car at time The velocity-time graph in Figure 4 shows the velocity, v m s t seconds for the first 35 seconds of its journey.
Read automatically from the paper; the printed page above is exact.
Show the answer and mark scheme
6(a)[2]
a
3
10
30
35
t
6
Distance travelled
(
)
20
+
35
=
×
30
2
Or =
1
1
×
10 30
×
+
(20 30)
×
+
××
5 30
2
2
1
1
Or
=
××
3 10
2
+
(20 30)
×
+
××
6 5
2
2
= 825 (m)
Distance travelled by
1
225
A
motorcycle
=
×
A
×
15
2
=
2
2
or 1
×
15
V
2
seen
Using equal distances travelled
by both at t = 20 to set up an
equation in A only (i.e. must also
use V = 15A if necessary)
225
A =
1 10 30 10 30
×
×
+
×
2
2
(
)
20 10
+
225
A
=
×
Or:
30
2
2
(
)
20 10
+
1 15
×
=
×
Or:
V
30
2
2
and (V = ) 60 = 15 A
(A =) 4
6(b)[2]
a
3
10
30
35
t
6
6(c)[2]
Distance travelled
(
)
20
+
35
=
×
30
2
Or =
1
1
×
10 30
×
+
(20 30)
×
+
××
5 30
2
2
1
1
Or
=
××
3 10
2
+
(20 30)
×
+
××
6 5
2
2
= 825 (m)
6(d)[4]
Distance travelled by
1
225
A
motorcycle
=
×
A
×
15
2
=
2
2
or 1
×
15
V
2
seen
Using equal distances travelled
by both at t = 20 to set up an
equation in A only (i.e. must also
use V = 15A if necessary)
225
A =
1 10 30 10 30
×
×
+
×
2
2
(
)
20 10
+
225
A
=
×
Or:
30
2
2
(
)
20 10
+
1 15
×
=
×
Or:
V
30
2
2
and (V = ) 60 = 15 A
(A =) 4
Make a free account to save your answers and see your weak topics and ask the AI why a wrong answer is wrong.