Mathematics · Oct / Nov 2025 · Paper 51 · Question 5
YMA01
As printed in the paper
The question as text
5. P N 30 4 kg Figure 3 A box of mass 4 kg is placed on a rough horizontal surface. A force of magnitude P newtons, acting at 30° to the horizontal, is applied to the box, as shown in Figure 3. The coefficient of friction between the box and the surface is 2 3 The box is modelled as a particle.
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Show the answer and mark scheme
5(a)[6]
R
P
F
4g
Resolve horizontally
P
cos30
°=
F
Resolve vertically
°+
=
P
sin30
R
4
g
3
2
P
=
R
2
3
1
3 3
+
=
P
4
g
2
4
(
P =
) 22 or 21.8
5(b)[5]
N.B. If they increase their value
of P by 25, treat as an MR i.e.
they can score all three M marks
in (b) and M1A1ft in (c) if they get
v = 4.7 or 4.74.
(R = 26.7)
25sin30
°+
R
=
4
g
Equation of motion
25cos30
°−
F
=
4
a
2
(
)
°−
−
°=
25cos30
4
g
25sin30
4
a
3
(
)
0.96 or 0.963 ms−
2
5(c)[2]
e.g.
2
=
××
v
2
a
1.5
(
)
1.7 or 1.70 ms−
1
Acceleration = (
)
6a i
3 ms−
2
Decceleration = (
)
ii
6 ms−
2
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