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Mathematics · May / June 2024 · Paper 51 · Question 7

YMA01

As printed in the paper

The question as text

7. [In this question, the horizontal unit vectors i and j are directed due east and due north respectively and position vectors are given relative to a fixed origin O.] Two speedboats, A and B, are each moving with constant velocity. • the velocity of A is 40 km h –1 due east –1 on a bearing of angle α (0° < α < 90°), where tan 4 • the velocity of B is 20 km h 3 The boats are modelled as particles.

Read automatically from the paper; the printed page above is exact.

Show the answer and mark scheme
  • 7(a)[2]

    B

    to an answer

    j ( km h1)

    =

    16

    i

    +

    12

  • 7(b)[2]

    (

    s

    =

    ) (10

    i

    +

    5 ) + (16

    j

    i

    +

    12 )

    j or (10 16 )

    +

    i

    +

    (5 12 )

    +

    j

    t

    t

    t

    s

    r

    i

    j

    i

    j

    [

    j

    i

    ]

  • 7(c)[2]

    AB

    = −=

    (10

    +

    5 ) + (16

    t

    +

    12 )

    −

    20

    +

    40

    t

    [

    ]

    =

    (10

    −

    24 )

    i

    +

    (12

    −

    15) km

    j

    *

    AB

    t

    t

  • 7(d)[3]

    10

    −

    24

    =

    0 and 12

    −

    15

    =

    0

    OR 40t =10 + 16t and 20 = 5 + 12t

    t

    t

    5

    5

    t =

    and

    or one correct t value which is then used in the other

    12

    4

    equation correctly to show that the equation is not true.

    Different t values oe so never collide*

    ALT 1:

    (10

    −

    24 )

    t

    2

    +

    (12

    t

    −

    15)

    2

    =

    0

    (i.e.

    720

    t

    2

    −

    840

    t

    +

    325

    =

    0

    ) M1

    ×

    ( 840)

    −

    2

    −

    4 720 325 (

    ×

    = −

    230,400)

    <

    0

    A1

    Or roots 7

    4

    ±

    i

    (calculator)

    12

    No real roots oe so never collide* A1*

    N.B. Must see justification for ‘no real roots’ to score either of the A

    marks.

    ALT 2:

    Finds minimum value of

    720

    2

    −

    840

    +

    325

    or its square M1

    t

    t

    root using derivative or completing the square or calculator

    (at t = 7

    80 or 80 or

    AB = −

    4

    i

    −

    8

    j

    12 ) A1

    so never collide* A1*

    10

    24

    12

    15

  • 7(e)[4]

    −

    t

    =

    t

    −

    oe

    25

    t =

    or 0.69 or better

    36

    25

    25

    AB

    =

    (10

    −

    24

    ×

    )

    i

    +

    (12

    ×

    −

    15)

    j

    (km)

    36

    36

    2

    AB =

    20 3

    , 9.4 or better (km)

    Notes

    M1: Condone sign errors and sin/cos confusion but both components

    3

    must be resolved. Allow if they use

    cos( ) or similar.

    7(a)

    5

    If 12

    i

    +

    16

    j appears without working, award M1A0.

    A1: cao

    7(b)

    M1: Correct structure, condone slips

    A1ft: ft on their answer to (a)

    7(c)

    M1: Allow −

    r

    s . r and s must be substituted.

    A1*: Correct given answer, correctly obtained

    N.B. Need to see AB

    at the start or finish for the A1* and answer must

    be exactly as printed, ignoring [] and km.

    7(d)

    M1: They may use

    r

    s with both i and j cpts equated.

    =

    A1: Need both t values. Accept 0.42 or better and 1.25.

    A1*: Correct conclusion

    7(e)

    M1: Correct method

    A1: cao

    M1: Sub their calculated t value into AB

    or BA

    , seen or implied, oe.

    Note that this is an independent M mark.

    A1: cao

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