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Mathematics · May / June 2023 · Paper 61 · Question 3

YMA01

As printed in the paper

The question as text

3. Jim records the length, l mm, of 81 salmon. The data are coded using x = l – 600 and the following summary statistics are obtained. n = 81 ∑x = 3711 ∑x 2 = 475 181

Read automatically from the paper; the printed page above is exact.

Show the answer and mark scheme
  • 3(a)[3]

    =

    3711 81 600

    +

    ×

    =

    52311

    [

    ]

    [

    ]

    l

    x =

    =

    45.814...

    81

    "52311"

    l

    =

    "45.814..." 600

    +

    l

    =

    81

    l

    =

    645.81...

    awrt 646

  • 3(b)[2]

    475181

    3711

    2

    2

    34088381

    "52311"

    [

    ]

    [

    ]

    2

    =

    −

    =

    3767

    Var( )

    L

    =

    −

    x

    81

    81

    81

    81

    =

    3767.43...

    l

    2

    =

    3767.43...

    = 3767.43… awrt 3770

    40

  • 3(c)[1]

    The answer is a drawing: see the picture of this mark scheme row.

  • 3(d)[3]

    IQR = 5400 – 3800 [= 1600]

    5400 1.5 "1600"

    +

    ×

    [= 7800] or3800 1.5 "1600"

    −

    ×

    [= 1400]

    7800 > 7700 and 1400 < 1600 therefore there are no outliers

    Notes

    (a)

    Allow 45.8 or better. Ignore labels

    M1 for a correct method to find x or

    l

    M1 for a correct method to find l ft their x if it is clearly labelled or it comes from 3711

    81

    if it is clearly labelled or comes from 3711 81 600

    +

    ×

    their

    l

    A1 awrt 646 or 17437

    or 52311

    oe

    27

    81

    M1 correct method to find Var (X) implied by awrt 3770 or a correct method to find Var (L) ft their

    (b)

    or Allow calculation of sd[

    ]

    =

    awrt 61.4

    Ignore labels

    l

    x

    A1 awrt 3770 labelled clearly as Var(L) or Var (L) = Var(X) or

    =

    stated or variance is not

    l

    x

    34088381

    "52311"

    changed by coding is stated or they have gained the answer from

    −

    81

    81

    B1 cao

    (c)

    M1 correct method to find IQR. May be implied by a correct limit.

    (d)

    NB 1.5 (5400

    ×

    −

    3800)

    =

    2400

    M1 for a correct method to find the upper or the lower outlier boundary.

    A1 both 7800 and 1400 correct and 7700 and 1600 (as the minimum not IQR) seen and explicitly

    stating no outliers

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