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Mathematics · May / June 2022 · Paper 61 · Question 3

YMA01

As printed in the paper

The question as text

3. Gill buys a bag of logs to use in her stove. The lengths, l cm, of the 88 logs in the bag are summarised in the table below. Length (l) Frequency ( f ) 15 < l  20 19 20 < l  25 35 25 < l  27 16 27 < l  30 15 30 < l  40 3 A histogram is drawn to represent these data. The bar representing logs with length 27 < l  30 has a width of 1.5 cm and a height of 4 cm.

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  • 3(a)[3]

    Width = 2.5 (cm)

    or 4

    Height = 35

    ×

    6

    ÷

    "2.5"

    5 ×

    7

    or 6cm2 = 15 (logs) or 14cm2 = 35 (logs) oe

    15

    = 5.6 (cm)

    25

    25.5

    Median [

    ]

    allow [

    ]

    =

    20

    +

    ×

    5

    20

    +

    ×

    5

  • 3(b)[2]

    35

    35

    = 23.57… allow 23.64….

    awrt 23.6 A1

  • 3(c)[1]

    19 + 35 + 8 (= 62*) or 88 – 3 – 15 – 8 (= 62*)

    B1cso*

    P(4 logs fit) = 62

    61

    60

    59

  • 3(d)[2]

    ×

    ×

    ×

    M1

    88

    87

    86

    85

    = 0.23922….

    awrt 0.239 A1

    924

    [

    ]

  • 3(e)(i)[3]

    mean of

    y =

    =

    10.5

    M1

    88

    mean of

    (

    "10.5" 255

    )

    2

    w =

    +

    ×

    M1

    = 531

    A1

    12862

    (

    ) [

    2

    ]

  • 3(e)(ii)[3]

    variance of

    y =

    −

    "10.5"

    =

    35.909...

    M1

    88

    variance of

    "35.909" 4

    w =

    ×

    or

    "35.909" 0.5

    ÷

    2

    M1

    = 143.636…

    awrt 144 A1

    Notes

    (a)

    B1

    2.5 oe

    Correct method to relate area to number of logs (may be implied by “their w” × “their h” = 14)

    M1

    5.6 oe

    A1

    (b)

    10

    For a correct fraction multiplied by 5. Allow working downwards e.g. [

    ]

    25

    5

    M1

    −

    ×

    35

    Correct answer from correct working. Allow exact fraction.

    A1

    (c)

    2 (16) for 8. Allow equivalent methods

    54

    =

    26 25

    A correct calculation seen. Allow 1

    x−

    −

    70 54

    −

    27 25

    −

    B1

    NB: 26 + x = 88→ x = 62 is B0.

    Minimum working required 54 + 8 or 70 – 8 or 54 70

    +

    2

    (d)

    n

    n

    −

    1

    n

    −

    2

    n

    −

    3

    For

    ×

    ×

    ×

    (allow any n < 88)

    M1

    88

    87

    86

    85

    A1

    awrt 0.239

    SC

    With replacement awrt 0.246 scores M1A0

    (e)(i)

    Correct method for finding mean of y (implied by 10.5) or for equation0.5

    w−

    88 255

    ×

    M1

    and 46728

    46728

    Correct method for finding mean of w or

    w =

    M1

    88

    Cao

    A1

    (ii)

    Correct method for finding variance of y (implied by awrt 35.9)

    M1

    0.25

    2

    255

    2

    88

    255

    12862

    or

    w

    +

    ×

    −

    w

    =

    24825208

    Correct method for finding variance of w or

    w =

    2

    24825208

    and

    −

    "531"

    2

    M1

    88

    P(

    ∪

    )

    =

    P(

    )

    +

    P(

    )

    −

    P(

    ∩

    )

    P(

    '

    ∩

    )

    =

    P(

    ∪

    )

    −

    P(

    )

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