Mathematics · May / June 2024 · Paper 42 · Question 5

9 125x final answer [2]

kx

or B1 for answer 125 m x 9 or for correct answer seen then spoilt

6 − n 2 oe final answer [2]

B1 for answer of form 6k oe − k or answer of the form 1 oe 6 or for correct answer seen

3x3 + 2x2 –37x + 12 final answer [3]

B2 for correct expansion of three brackets unsimplified or for simplified four-term expression of correct form with 3 terms correct

or B1 for correct expansion of two brackets with at least 3 terms out of 4 correct

eliminates the fraction correctly eg (3x + 5) (x – 2) + 7 = x (x – 2) 3x2 + 5x –6x – 10 + 7 = x2 – 2x oe leading to 2x2 + x – 3 = 0 [8]

M1 B2 B1 for 3x2 + 5x –6x –10 [ + 7] oe seen with at least 3 terms correct A1 dep on M1 B2 with no errors or omissions

( )( ) + − 2 x 3 x 1 −1.5 oe and +1 [4]

M2 or M1 for (2x + a)(x + b) where ab = −3 or 2b + a = [+]1 or for partial factors 2x(x – 1) + 3(x – 1) or x(2x + 3) –[1](2x + 3) B1

π + π × [TSA cylinder =] 2 x 2 2 x 3 x π 2 4 (5 ) y π 2 + [TSA hemisphere=] (5 ) y 2 Leading to π + π = π + π 2 x 2 6 x 2 50 y 2 25 y oe 2 75 y 2 x 2 = 8 [4]

M1 M1 M1 dep M1M1 A1 dep on M1M1M1