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Mathematics · May / June 2024 · Paper 42 · Question 4

0580

As printed in the paper

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  • 4(a)(i)[3]

    22 620 cao [3]

    B2 for 7200π or 22 608 to 22 629 1

    or M1 for × π × 2 × oe 12 [ figs 1] 2

  • 4(a)(ii)[5]

    8840 or 8850 or 8836 to 8850. M [5]

    M1 for cos COM = 6 12 oe or sin AOC = 6 12 oe theirCOD × π × 2

    M1 for 12 oe 360 1 ( )

    M1 for × 12 2 × sin theirCOD oe 2 M1dep for (their area of sector COD– their area of triangle COD) ×100 dep on at least M1M1 oe

  • 4(b)[3]

    647 or 646.8 [3]

    M2 for 2.2 m = oe × × 42 35 0.2

    or M1 for [vol of stone =] 42×35×0.2 oe If 0 scored

    SC1 for answer figs 647 or figs 6468

  • 4(c)[4]

    46.1 or 46.12 to 46.14 [4]

    M3 for 15 = tan oe 2 + 2 8 12

    or M2 for 82 + 122 oe or 82 + 122 + 152 oe

    or M1 for identifying the angle GAC

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