Mathematics · Oct / Nov 2023 · Paper 41 · Question 5
0580
As printed in the paper
Show the answer and mark scheme
5(a)[5]
27.3 or 27.32 to 27.33 [5]
M4 for tan[∠ACD] = 83.2 oe 83.2 tan38 + 54.5
or M3 for [AC =] 83.2 tan38 +54.5 oe or for [CD =] 2 83.2 83.2 2 + − − 54.5 2(54.5) cos(180 38) sin38 sin38 oe
or M2 for [AB =] 83.2 tan38 oe or for [BD =] 83.2 oe sin 38
or M1 for tan38 = 83.2 AB oe or sin38 = 83.2 BD oe
5(b)[2]
Centre marked at midpoint of FG. and Angle in a semi-circle is 90 [3]
B2 B1 for marking the centre at mid-point of FG
5(c)[7]
10.8 or 10.81 to 10.82 [7]
B2 for 72 180
or M1 for [× 6] + + 4 5 6 and, for triangle PQR
B4 for [angle R=]82.8 or 82.81 to 82.83
or B3 for [cosR =] 5 40 oe or better + − 4 2 5 2 6 2
or M2 for 2 ×× 4 5
or M1 for 62 = 42 + 52 – 2×4×5×cosR After 0 scored for triangle PQR,
SC1 for [P =] 55.8 or 55.77 to 55.78 or [ ]41.4 = Q or 41.40 41.41 to
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