Mathematics · Oct / Nov 2023 · Paper 41 · Question 4
0580
As printed in the paper
Show the answer and mark scheme
4(a)(i)[2]
5 5 2 9 , 4 9 5 9 , 4 9 [2]
B1 for 2 5 and a pair of probabilities for spinner B that sum to 1
4(a)(ii)[3]
1 3 oe [2]
FT dep their tree diagram
M1 for 3 5 × their 5 9 2 3 oe [1]
FT dep 1 – their 1 3
4(b)[1]
72 [1]
4(c)[3]
20 81 oe [3]
M2 for 2 4 [× 2] + 2 2 × × oe 9 9 9 9
or M1 for 2 4 or 2 2 × × oe 9 9 9 9
4(d)[2]
n− 1 5 4 × [ ] oe final answer 9 9 [2]
n− 1 5
M1 for seen 9
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