Note AcademyNote Academy

Momentum and Newton’s laws of motion

3.1

What the syllabus asks of you

  • understand that mass is the property of an object that resists change in motion
  • recall F = ma and solve problems using it, understanding that acceleration and resultant force are always in the same direction
  • define and use linear momentum as the product of mass and velocity
  • define and use force as rate of change of momentum
  • state and apply each of Newton’s laws of motion
  • describe and use the concept of weight as the effect of a gravitational field on a mass and recall that the weight of an object is equal to the product of its mass and the acceleration of free fall

Read the notes first

Chapter 3: Momentum and Newton's laws of motion

Open the notes →

Drill this topic

Every question on Momentum and Newton’s laws of motion, untimed, marked as you go.

Start drill →

Make a worksheet

Choose the years and how many questions, then print it with the answers on separate pages.

Make a worksheet →

123 questions

1May / June 2026 · Paper 11 · Q9
Show mark scheme →
Athe contact force acting on the book due to the table
Bthe contact force acting on the table due to the book
Cthe friction force between the book and the table
Dthe gravitational force acting on the Earth due to the book

Mark scheme

2May / June 2026 · Paper 12 · Q9
Show mark scheme →
Aforce per unit time
Bmass per unit velocity
Cproduct of force and time
Dproduct of mass and velocity

Mark scheme

3May / June 2026 · Paper 12 · Q11
Show mark scheme →
A44.1 N
B3560 N
C3600 N
D3640 N

Mark scheme

4May / June 2026 · Paper 12 · Q12
Show mark scheme →
AThe forces act in opposite directions.
BThe forces act on different objects.
CThe forces act on objects in contact.
DThe forces are of equal magnitude.

Mark scheme

5May / June 2026 · Paper 13 · Q11
Show mark scheme →
Athe force the object experiences due to gravity
Bthe momentum of the object before a collision
Cthe resistance of the object to changes in motion
Dthe weight of the object as measured by a balance

Mark scheme

6May / June 2026 · Paper 14 · Q9
Show mark scheme →
At = (mv + mΔv)/F
Bt = mΔv/F
Ct = F/(mΔv)
Dt = F/(mv + mΔv)

Mark scheme

7May / June 2026 · Paper 14 · Q10
Show mark scheme →
AN = P + W
BN > P
CN = W
DN > W

Mark scheme

8Oct / Nov 2025 · Paper 11 · Q11
Show mark scheme →
A500 N
B5000 N
C25 000 N
D50 000 N

Mark scheme

9Oct / Nov 2025 · Paper 11 · Q12
Show mark scheme →
AWa/g + W
BWa/g
CWa/g – W
DWa + W

Mark scheme

10Oct / Nov 2025 · Paper 12 · Q8
Show mark scheme →
AIt is equal to the mass of the object multiplied by its acceleration.
BIt is equal to the resultant force when the object falls at terminal (constant) velocity.
CIt is the force acting on the object due to a gravitational field.
DIt is the property of the object that resists change in motion.

Mark scheme

11Oct / Nov 2025 · Paper 13 · Q11
Show mark scheme →
A500 N
B5000 N
C25 000 N
D50 000 N

Mark scheme

12Oct / Nov 2025 · Paper 13 · Q12
Show mark scheme →
A\frac{Wa}{g} + W
B\frac{Wa}{g}
C\frac{Wa}{g} - W
DWa + W

Mark scheme

13Oct / Nov 2025 · Paper 14 · Q4
Show mark scheme →
AGraph A: p constant (horizontal line)
BGraph B: p increasing with decreasing gradient (curve)
CGraph C: p increasing linearly (straight line through origin)
DGraph D: p increasing with increasing gradient (curve)

Mark scheme

14Oct / Nov 2025 · Paper 14 · Q8
Show mark scheme →
Amass: different, weight: different
Bmass: different, weight: same
Cmass: same, weight: different
Dmass: same, weight: same

Mark scheme

15May / June 2025 · Paper 11 · Q10
Show mark scheme →
Aair resistance and force on gases
Bair resistance and thrust
Cforce on gases and thrust
Dthrust and weight

Mark scheme

16May / June 2025 · Paper 11 · Q11
Show mark scheme →
A3.1 N
B4.0 N
C6.9 N
D7.1 N

Mark scheme

17May / June 2025 · Paper 12 · Q7
Show mark scheme →
A20 m s–1
B40 m s–1
C80 m s–1
D100 m s–1

Mark scheme

18May / June 2025 · Paper 12 · Q9
Show mark scheme →
A2.1 kN
B17 kN
C18 kN
D162 kN

Mark scheme

19May / June 2025 · Paper 12 · Q11
Show mark scheme →
Athe force exerted by the cyclist on the pedals
Bthe forward push of the road on the back wheel
Cthe tension in the cycle chain
Dthe total air resistance and friction force

Mark scheme

20May / June 2025 · Paper 13 · Q9
Show mark scheme →
AWhen a force acts on a body that is free to move, the force is the product of the mass of the body and its acceleration.
BWhen a force acts on a body that is free to move, the force is the rate of change of momentum of the body.
CWhen a force acts on a body that is free to move, the force is the work done by the force divided by the distance moved by the body.
DWhen a force acts on a lever and causes a moment, the force is the moment divided by the perpendicular distance of the force from the pivot.

Mark scheme

21May / June 2025 · Paper 14 · Q7
Show mark scheme →
Aforce = change of momentum
Bforce = mass × acceleration
Cforce = moment / perpendicular distance from the pivot
Dforce = work done / displacement in the direction of the force

Mark scheme

22Feb / March 2025 · Paper 12 · Q3
Show mark scheme →
A13 kg
B1000 kg
C1300 kg
D10 000 kg

Mark scheme

23Feb / March 2025 · Paper 12 · Q8
Show mark scheme →
A1.2mg
Bmg
C0.8mg
D0

Mark scheme

24Oct / Nov 2024 · Paper 11 · Q10
Show mark scheme →
A0.032 m s–2
B0.32 m s–2
C0.61 m s–2
D0.65 m s–2

Mark scheme

25Oct / Nov 2024 · Paper 11 · Q11
Show mark scheme →
AmvΔt
Bmv/Δt
C½mv²Δt
D½mv²/Δt

Mark scheme

26Oct / Nov 2024 · Paper 12 · Q9
Show mark scheme →
A16 N
B37 N
C53 N
D91 N

Mark scheme

27Oct / Nov 2024 · Paper 13 · Q9
Show mark scheme →
A0
B1500 N
C2000 N
D4000 N

Mark scheme

28May / June 2024 · Paper 11 · Q9
Show mark scheme →
Agraph of v against t: starts at 0, increasing with increasing gradient (concave up)
Bgraph of v against t: starts at 0, S-shaped, gradient increasing then decreasing, levelling off
Cgraph of v against t: rectangular pulse, constant positive v then drops to zero
Dgraph of v against t: rises linearly to a peak then falls linearly through zero to negative

Mark scheme

29May / June 2024 · Paper 11 · Q10
Show mark scheme →
Amass: its momentum divided by its velocity; weight: the work done in lifting it one metre
Bmass: the gravitational force on it; weight: the property that resists its acceleration
Cmass: the pull of the Earth on it; weight: its mass divided by the acceleration of free fall
Dmass: the property that resists its acceleration; weight: the pull of the Earth on it

Mark scheme

30May / June 2024 · Paper 11 · Q13
Show mark scheme →
A0.20 N s
B0.50 N s
C1.5 N s
D3.5 N s

Mark scheme

31May / June 2024 · Paper 13 · Q6
Show mark scheme →
A2.0 N
B3.0 N
C5.0 N
D8.0 N

Mark scheme

32May / June 2024 · Paper 13 · Q7
Show mark scheme →
AThey act in opposite directions.
BThey act on different objects.
CThey are the same type of force.
DThey cause an object to be in equilibrium.

Mark scheme

33Feb / March 2024 · Paper 12 · Q2
Show mark scheme →
A0.47 m s⁻²
B1.4 m s⁻²
C1.9 m s⁻²
D3.3 m s⁻²

Mark scheme

34Feb / March 2024 · Paper 12 · Q4
Show mark scheme →
AIt increases uniformly with respect to time.
BIt is constant but not zero.
CIt is proportional to the displacement from point P.
DIt is zero.

Mark scheme

35Feb / March 2024 · Paper 12 · Q15
Show mark scheme →
Athe product of mass and acceleration
Bthe product of mass and velocity
Cthe rate of change of momentum
Dthe rate of transfer of energy

Mark scheme

36Oct / Nov 2023 · Paper 11 · Q7
Show mark scheme →
AIt is equal to the weight of the man.
BIt is greater than the force exerted by the floor on the man.
CIt is less than the force exerted by the floor on the man.
DIt is less than the weight of the man.

Mark scheme

37Oct / Nov 2023 · Paper 11 · Q8
Show mark scheme →
A20 N
B60 N
C20 kN
D60 kN

Mark scheme

38Oct / Nov 2023 · Paper 12 · Q7
Show mark scheme →
A3.5 N
B3.9 N
C4.5 N
D6.3 N

Mark scheme

39Oct / Nov 2023 · Paper 12 · Q8
Show mark scheme →
Athe acceleration of the object per unit mass
Bthe change in kinetic energy of the object per unit time
Cthe change in momentum of the object per unit time
Dthe change in velocity of the object per unit time

Mark scheme

40Oct / Nov 2023 · Paper 13 · Q7
Show mark scheme →
AMass has a magnitude and a direction.
BMass resists changes in motion.
CThe greater the mass of an object, the greater its acceleration when falling in a vacuum.
DThe mass of an object depends on its location.

Mark scheme

41Oct / Nov 2023 · Paper 13 · Q8
Show mark scheme →
A1.4 N
B2.3 N
C4.2 N
D7.0 N

Mark scheme

42May / June 2023 · Paper 11 · Q7
Show mark scheme →
A0.750 m s⁻¹
B3.00 m s⁻¹
C7.36 m s⁻¹
D29.4 m s⁻¹

Mark scheme

43May / June 2023 · Paper 11 · Q8
Show mark scheme →
A
B
C
D

Mark scheme

44May / June 2023 · Paper 12 · Q7
Show mark scheme →
Athe force the object experiences due to gravity
Bthe momentum of the object before a collision
Cthe resistance of the object to changes in motion
Dthe weight of the object as measured by a balance

Mark scheme

45May / June 2023 · Paper 12 · Q8
Show mark scheme →
A0.613 m s–2
B0.654 m s–2
C9.81 m s–2
D10.5 m s–2

Mark scheme

46May / June 2023 · Paper 13 · Q7
Show mark scheme →
A0.36 N
B0.90 N
C2.3 N
D900 N

Mark scheme

47May / June 2023 · Paper 13 · Q8
Show mark scheme →
Atotal resistive forces and driving force on a car
Bgravitational force between Earth and Moon
Csupport force and weight on a block
Dlift and weight on an aeroplane

Mark scheme

48Feb / March 2023 · Paper 12 · Q4
Show mark scheme →
A0.020 kg m s⁻¹
B0.10 kg m s⁻¹
C0.14 kg m s⁻¹
D0.50 kg m s⁻¹

Mark scheme

49Feb / March 2023 · Paper 12 · Q7
Show mark scheme →
A(mass × change in speed) × time taken
B\frac{mass × change in speed}{time taken}
C(change of momentum) × time taken
D\frac{change of momentum}{time taken}

Mark scheme

50Feb / March 2023 · Paper 12 · Q8
Show mark scheme →
A15 seconds
B150 seconds
C25 minutes
D250 minutes

Mark scheme

51Oct / Nov 2022 · Paper 11 · Q7
Show mark scheme →
Aforce per unit time
Bproduct of force and time
Cproduct of velocity and mass
Dvelocity per unit mass

Mark scheme

52Oct / Nov 2022 · Paper 11 · Q8
Show mark scheme →
A4.9 m s–2
B6.5 m s–2
C9.8 m s–2
D15 m s–2

Mark scheme

53Oct / Nov 2022 · Paper 12 · Q8
Show mark scheme →
AF/t
BFt/m
CFt
DF/(mt)

Mark scheme

54Oct / Nov 2022 · Paper 12 · Q9
Show mark scheme →
Amass 1.0 kg, weight 0.1 N
Bmass 1.0 kg, weight 10 N
Cmass 10 kg, weight 10 N
Dmass 10 kg, weight 100 N

Mark scheme

55Oct / Nov 2022 · Paper 13 · Q8
Show mark scheme →
A0.2 N
B1 N
C20 N
D100 N

Mark scheme

56May / June 2022 · Paper 11 · Q7
Show mark scheme →
AThe resultant force acting on the object is equal to its weight.
BThe resultant force acting on the object is equal to the product of its mass and its velocity.
CThe resultant force acting on the object is equal to the resistive force.
DThe resultant force acting on the object is equal to zero.

Mark scheme

57May / June 2022 · Paper 11 · Q8
Show mark scheme →
Aρv / A
Bρv² / A
CρAv
DρAv²

Mark scheme

58May / June 2022 · Paper 12 · Q7
Show mark scheme →
AThe forces act in opposite directions.
BThe forces act on different objects.
CThe forces act on objects in contact.
DThe forces are of equal magnitude.

Mark scheme

59May / June 2022 · Paper 12 · Q8
Show mark scheme →
A4.0 N
B6.0 N
C8.0 N
D12 N

Mark scheme

60May / June 2022 · Paper 13 · Q8
Show mark scheme →
Athe kinetic energy of the car
Bthe rate of change of kinetic energy of the car
Cthe resultant force on the car
Dthe velocity of the car

Mark scheme

61May / June 2022 · Paper 13 · Q9
Show mark scheme →
AN = P + W
BN > P + W
CN = W
DN > W

Mark scheme

62Feb / March 2022 · Paper 12 · Q7
Show mark scheme →
AThe acceleration of X is equal to force F divided by the mass of X.
BThe force that X exerts on Y is equal to F.
CThe force that X exerts on Y is less than F.
DThe force that X exerts on Y is less than the force that Y exerts on X.

Mark scheme

63Feb / March 2022 · Paper 12 · Q8
Show mark scheme →
A0.50 kN
B1.5 kN
C2.0 kN
D3.5 kN

Mark scheme

64Oct / Nov 2021 · Paper 11 · Q8
Show mark scheme →
AGraph A
BGraph B
CGraph C
DGraph D

Mark scheme

65Oct / Nov 2021 · Paper 11 · Q9
Show mark scheme →
AIf the object has mass then the field causes it to accelerate.
BIf the object has mass then the field causes it to have weight.
CIf the object has weight then the field causes it to accelerate.
DIf the object has weight then the field causes it to have mass.

Mark scheme

66Oct / Nov 2021 · Paper 11 · Q10
Show mark scheme →
A800 N
B2400 N
C3200 N
D5600 N

Mark scheme

67Oct / Nov 2021 · Paper 12 · Q8
Show mark scheme →
Athe property of the object that resists a change in motion
Bthe pull of the Earth on the object
Cthe total number of atoms in the object
Dthe weight of the object

Mark scheme

68Oct / Nov 2021 · Paper 12 · Q9
Show mark scheme →
AThe acceleration of Y is half the acceleration of X.
BThe acceleration of Y is the same as the acceleration of X.
CThe acceleration of Y is more than the acceleration of X, but less than twice the value.
DThe acceleration of Y is twice the acceleration of X.

Mark scheme

69Oct / Nov 2021 · Paper 13 · Q8
Show mark scheme →
A30 N
B270 N
C1800 N
D110 000 N

Mark scheme

70May / June 2021 · Paper 11 · Q8
Show mark scheme →
Aair resistance
Bforce of the exhaust gases on the rocket
Cforce of the rocket on the exhaust gases
Dgravitational force of the rocket on the Earth

Mark scheme

71May / June 2021 · Paper 12 · Q8
Show mark scheme →
Athe force W acting downwards on the Earth from the table
Bthe force W acting upwards on the book from the table
Cthe force W acting upwards on the Earth from the book
Dthe force W acting upwards on the table from the floor

Mark scheme

72May / June 2021 · Paper 13 · Q8
Show mark scheme →
Asinθ < m/M
Bcosθ < m/M
Csinθ > m/M
Dcosθ > m/M

Mark scheme

73May / June 2021 · Paper 13 · Q9
Show mark scheme →
A40 mN, 6.0 g
B3.0 N, 500 g
C10 N, 1 kg
D2.6 kN, 750 kg

Mark scheme

74Feb / March 2021 · Paper 12 · Q8
Show mark scheme →
Azero
B$\dfrac{2p}{t}$
C$\dfrac{2p\cos\theta}{t}$
D$\dfrac{2p\sin\theta}{t}$

Mark scheme

75Oct / Nov 2020 · Paper 12 · Q8
Show mark scheme →
AIf body X exerts a force on body Y, body Y exerts an equal and opposite force on body X.
BIf no resultant force acts on a body it has constant velocity.
CThe rate of change of momentum of a body is proportional to the resultant force acting on it and takes place in the direction of the force.
DThe total momentum of a system of interacting bodies is constant if there is no external force.

Mark scheme

76Oct / Nov 2020 · Paper 13 · Q8
Show mark scheme →
A0.36 N
B0.90 N
C2.3 N
D900 N

Mark scheme

77May / June 2020 · Paper 12 · Q7
Show mark scheme →
AGraph A
BGraph B
CGraph C
DGraph D

Mark scheme

78May / June 2020 · Paper 12 · Q8
Show mark scheme →
A67.3 N
B178 N
C250 N
D660 N

Mark scheme

79May / June 2020 · Paper 13 · Q8
Show mark scheme →
A\frac{mv - mu}{\Delta t} downwards
B\frac{mv - mu}{\Delta t} upwards
C\frac{mv + mu}{\Delta t} downwards
D\frac{mv + mu}{\Delta t} upwards

Mark scheme

80Feb / March 2020 · Paper 12 · Q8
Show mark scheme →
Adownwards, constant speed
Bdownwards, slowing down
Cupwards, constant speed
Dupwards, slowing down

Mark scheme

81Oct / Nov 2019 · Paper 11 · Q6
Show mark scheme →
A0.60 N
B0.80 N
C1.5 N
D2.0 N

Mark scheme

82Oct / Nov 2019 · Paper 11 · Q7
Show mark scheme →
AA body remains at constant velocity unless acted upon by a resultant force.
BA satellite in circular motion about the Earth has a constant velocity.
CA water drop leaving a spinning umbrella travels at a constant velocity.
DThe force acting on an object is equal to its change in momentum.

Mark scheme

83Oct / Nov 2019 · Paper 11 · Q8
Show mark scheme →
Athe acceleration of the object per unit mass
Bthe change in kinetic energy of the object per unit time
Cthe change in momentum of the object per unit time
Dthe change in velocity of the object per unit time

Mark scheme

84Oct / Nov 2019 · Paper 12 · Q7
Show mark scheme →
A1.4 N
B2.3 N
C4.2 N
D7.0 N

Mark scheme

85Oct / Nov 2019 · Paper 13 · Q7
Show mark scheme →
A
B
C
D

Mark scheme

86May / June 2019 · Paper 11 · Q9
Show mark scheme →
Atotal resistive forces and driving force on a car
Bgravitational attraction between Earth and Moon
Csupport force and weight on a block
Dlift and weight on an aeroplane

Mark scheme

87May / June 2019 · Paper 11 · Q11
Show mark scheme →
Azero
B0.5 mv
Cmv
D2mv

Mark scheme

88May / June 2019 · Paper 12 · Q9
Show mark scheme →
Athe force the object experiences due to gravity
Bthe momentum of the object before a collision
Cthe resistance of the object to changes in motion
Dthe weight of the object as measured by a balance

Mark scheme

89May / June 2019 · Paper 12 · Q10
Show mark scheme →
Ama
B2ma
C3ma
D4ma

Mark scheme

90Oct / Nov 2018 · Paper 11 · Q7
Show mark scheme →
A30 N
B270 N
C1800 N
D108 000 N

Mark scheme

91Oct / Nov 2018 · Paper 12 · Q7
Show mark scheme →
A
B
C
D

Mark scheme

92Oct / Nov 2018 · Paper 12 · Q8
Show mark scheme →
Amass on Q / kg: 1.0, weight on Q / N: 0.1
Bmass on Q / kg: 1.0, weight on Q / N: 10
Cmass on Q / kg: 10, weight on Q / N: 10
Dmass on Q / kg: 10, weight on Q / N: 100

Mark scheme

93Oct / Nov 2018 · Paper 13 · Q7
Show mark scheme →
A2.0 m s⁻²
B4.0 m s⁻²
C8.0 m s⁻²
D16 m s⁻²

Mark scheme

94Oct / Nov 2018 · Paper 13 · Q8
Show mark scheme →
A4.9 m s–2
B5.7 m s–2
C8.5 m s–2
D9.8 m s–2

Mark scheme

95Oct / Nov 2018 · Paper 13 · Q10
Show mark scheme →
A15 seconds
B150 seconds
C25 minutes
D250 minutes

Mark scheme

96May / June 2018 · Paper 11 · Q7
Show mark scheme →
A0.63 m s–2
B1.6 m s–2
C3.2 m s–2
D9.8 m s–2

Mark scheme

97May / June 2018 · Paper 12 · Q8
Show mark scheme →
A110 N
B220 N
C330 N
D550 N

Mark scheme

98May / June 2018 · Paper 13 · Q7
Show mark scheme →
Asinθ < m/M
Bcosθ < m/M
Csinθ > m/M
Dcosθ > m/M

Mark scheme

99Feb / March 2018 · Paper 12 · Q10
Show mark scheme →
A0.0010 N
B0.0054 N
C0.0090 N
D0.54 N

Mark scheme

100Oct / Nov 2017 · Paper 12 · Q10
Show mark scheme →
A\frac{(M + m)}{(M - m)} g
B\frac{(M - m)}{(M + m)} g
C\frac{M}{m} g
D\frac{m}{M} g

Mark scheme

101Oct / Nov 2017 · Paper 13 · Q8
Show mark scheme →
AIt is equal to the weight of the man.
BIt is greater than the force exerted by the floor on the man.
CIt is less than the force exerted by the floor on the man.
DIt is less than the weight of the man.

Mark scheme

102Oct / Nov 2017 · Paper 13 · Q9
Show mark scheme →
A2.3 N
B7.0 N
C2300 N
D7000 N

Mark scheme

103May / June 2017 · Paper 11 · Q7
Show mark scheme →
AThe acceleration of the truck decreases as the fuel is consumed.
BThe acceleration of the truck increases as the fuel is consumed.
CThe acceleration of the truck remains constant.
DThe acceleration of the truck is zero and the truck moves at a constant velocity.

Mark scheme

104May / June 2017 · Paper 11 · Q10
Show mark scheme →
A500 N
B5000 N
C25 000 N
D50 000 N

Mark scheme

105May / June 2017 · Paper 12 · Q7
Show mark scheme →
AGraph A: F increases linearly from zero
BGraph B: F starts high, decreases to a minimum, then increases
CGraph C: F starts at zero, rises to a maximum, then falls back to zero
DGraph D: F starts high and decreases linearly to zero

Mark scheme

106May / June 2017 · Paper 12 · Q8
Show mark scheme →
A$m\sqrt{2gh_1} - m\sqrt{2gh_2}$
B$m\sqrt{2gh_1} + m\sqrt{2gh_2}$
C$m\sqrt{2g(h_1 - h_2)}$
D$m\sqrt{2g(h_1 + h_2)}$

Mark scheme

107May / June 2017 · Paper 12 · Q9
Show mark scheme →
Athe force W acting downwards on the Earth from the table
Bthe force W acting upwards on the book from the table
Cthe force W acting upwards on the Earth from the book
Dthe force W acting upwards on the table from the floor

Mark scheme

108May / June 2017 · Paper 13 · Q7
Show mark scheme →
Aspeed-time graph: speed decreasing with decreasing gradient (concave up curve) from initial speed to zero at time t
Bspeed-time graph: speed decreasing linearly (straight line) from initial speed to zero at time t
Cspeed-time graph: speed decreasing with an S-shaped curve from initial speed to zero at time t
Dspeed-time graph: speed decreasing with increasing gradient (concave down curve) from initial speed to zero at time t

Mark scheme

109May / June 2017 · Paper 13 · Q9
Show mark scheme →
A16 N
B37 N
C53 N
D91 N

Mark scheme

110May / June 2017 · Paper 13 · Q10
Show mark scheme →
A0.010 N
B0.020 N
C0.067 N
D0.44 N

Mark scheme

111Feb / March 2017 · Paper 12 · Q8
Show mark scheme →
A0.40 N
B0.93 N
C4.0 N
D39 N

Mark scheme

112Feb / March 2017 · Paper 12 · Q9
Show mark scheme →
Aρv/A
Bρv²/A
CρAv
DρAv²

Mark scheme

113Oct / Nov 2016 · Paper 11 · Q9
Show mark scheme →
Aspeed-time graph: speed zero until a time, then increases linearly
Bspeed-time graph: speed zero until a time, then increases with increasing gradient
Cspeed-time graph: speed zero until a time, then rises sharply to a constant value
Dspeed-time graph: speed zero until a time, then rises smoothly to a constant value

Mark scheme

114Oct / Nov 2016 · Paper 11 · Q11
Show mark scheme →
Ama
B2ma
C3ma
D4ma

Mark scheme

115Oct / Nov 2016 · Paper 11 · Q12
Show mark scheme →
AP is the equal and opposite force to Q and both are forces of contact.
BQ is the equal and opposite force to P and both are gravitational forces.
CR is the equal and opposite force to S and both are forces of contact.
DS is the equal and opposite force to Q and both are gravitational forces.

Mark scheme

116Oct / Nov 2016 · Paper 12 · Q12
Show mark scheme →
A24 N
B240 N
C2400 N
D24 000 N

Mark scheme

117Oct / Nov 2016 · Paper 13 · Q9
Show mark scheme →
Aspeed-time graph: speed increases linearly from zero after a delay
Bspeed-time graph: speed increases with increasing gradient after a delay
Cspeed-time graph: speed rises sharply then becomes constant after a delay
Dspeed-time graph: speed rises smoothly (S-shape) then becomes constant after a delay

Mark scheme

118Oct / Nov 2016 · Paper 13 · Q11
Show mark scheme →
Ama
B2ma
C3ma
D4ma

Mark scheme

119Oct / Nov 2016 · Paper 13 · Q12
Show mark scheme →
AP is the equal and opposite force to Q and both are forces of contact.
BQ is the equal and opposite force to P and both are gravitational forces.
CR is the equal and opposite force to S and both are forces of contact.
DS is the equal and opposite force to Q and both are gravitational forces.

Mark scheme

120May / June 2016 · Paper 11 · Q11
Show mark scheme →
A2.4 m s–1
B6.9 m s–1
C24 m s–1
D47 m s–1

Mark scheme

121May / June 2016 · Paper 12 · Q9
Show mark scheme →
A$p_1 = 0.15\ \mathrm{kg\,m\,s^{-1}}$, $p_2 = 0.65\ \mathrm{kg\,m\,s^{-1}}$
B$p_1 = 0.20\ \mathrm{kg\,m\,s^{-1}}$, $p_2 = 0.30\ \mathrm{kg\,m\,s^{-1}}$
C$p_1 = 0.30\ \mathrm{kg\,m\,s^{-1}}$, $p_2 = 0.20\ \mathrm{kg\,m\,s^{-1}}$
D$p_1 = 0.65\ \mathrm{kg\,m\,s^{-1}}$, $p_2 = 0.15\ \mathrm{kg\,m\,s^{-1}}$

Mark scheme

122May / June 2016 · Paper 13 · Q11
Show mark scheme →
A3.1 × 10⁻⁸ m s⁻²
B6.3 × 10⁻⁷ m s⁻²
C3.2 × 10⁻³ m s⁻²
D6.4 × 10⁻² m s⁻²

Mark scheme

123Feb / March 2016 · Paper 12 · Q9
Show mark scheme →
AWhen a force acts on a body that is free to move, the force is the product of the mass of the body and its acceleration.
BWhen a force acts on a body that is free to move, the force is the rate of change of momentum of the body.
CWhen a force acts on a body that is free to move, the force is the work done by the force divided by the distance moved by the body.
DWhen a force acts on a lever and causes a moment, the force is the moment divided by the perpendicular distance of the force from the pivot.

Mark scheme