Inheritance
17.3What the syllabus asks of you
- Describe inheritance as the transmission of genetic information from generation to generation
- Define an allele as an alternative form of a gene
- Understand and use the terms: dominant, recessive, phenotype, genotype, homozygous and heterozygous
- Use genetic diagrams, including Punnett squares, to predict the results of monohybrid crosses and calculate phenotypic ratios, limited to 1 : 1 and 3 : 1 ratios
- Explain why observed ratios often differ from expected ratios, especially when there are small numbers of offspring
- State that two identical homozygous individuals that breed together will be pure-breeding
- Explain codominance by reference to the inheritance of the ABO blood groups (phenotypes A, B, AB, O, gene alleles IA, IB and Io)
- Describe the determination of sex in humans (XX and XY chromosomes)
- Describe a gene mutation as a random change in the base sequence of DNA, using sickle cell anaemia as an example
- Describe a chromosome mutation as a change in the chromosome number or structure, using Down’s syndrome as an example (47 chromosomes instead of 46)
- State that mutation, meiosis, random mating and random fertilisation are sources of genetic variation in populations
- Understand that ionising radiation and some chemicals increase the rate of mutation
Read the notes first
Chapter 17: Inheritance
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Every question on Inheritance, untimed, marked as you go.
Make a worksheet
Choose the years and how many questions, then print it with the answers on separate pages.
13 questions
1Oct / Nov 2020 · Paper 11 · Q37Show mark scheme →
A1 black : 1 white
B1 black : 3 white
C1 black : 2 grey : 1 white
D3 black : 1 white
Mark scheme
2Oct / Nov 2020 · Paper 12 · Q37Show mark scheme →
A1 black : 1 white
B1 black : 3 white
C1 black : 2 grey : 1 white
D3 black : 1 white
Mark scheme
3Oct / Nov 2020 · Paper 12 · Q38Also set in Oct / Nov 2020 Paper 11Show mark scheme →
AA
BB
CC
DD
Mark scheme
4May / June 2020 · Paper 11 · Q38Show mark scheme →
ABB × BB
BBB × Bb
CBb × Bb
DBb × bb
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5May / June 2020 · Paper 12 · Q38Show mark scheme →
AThe alleles for light brown colour are dominant.
BThe male sheep is heterozygous and the allele for black colour is dominant.
CThe male sheep is homozygous and the allele for black colour is codominant.
DThe male sheep is homozygous and the allele for black colour is dominant.
Mark scheme
6May / June 2020 · Paper 12 · Q39Also set in May / June 2020 Paper 11Show mark scheme →
AAB and B only
BAB and A only
CA, B and AB only
DA, B, AB and O
Mark scheme
7May / June 2020 · Paper 12 · Q40Also set in May / June 2020 Paper 11Show mark scheme →
AThey cannot undergo mutation.
BThey give a greater chance of survival than recessive alleles.
CThey give the same phenotype in heterozygotes and homozygotes.
DThey occur less frequently in the population than recessive alleles.
Mark scheme
8Oct / Nov 2019 · Paper 11 · Q39Show mark scheme →
A1 : 1 A : B
B1 : 1 AB : O
C1 : 1 : 1 A : B : O
D1 : 1 : 1 : 1 A : B : AB : O
Mark scheme
9Oct / Nov 2019 · Paper 12 · Q39Show mark scheme →
A1 in 2
B1 in 4
C1 in 8
D3 in 4
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10Oct / Nov 2019 · Paper 12 · Q40Also set in Oct / Nov 2019 Paper 11Show mark scheme →
AA dominant characteristic is seen in the phenotype of a heterozygote.
BA homozygous genotype may be either dominant or recessive.
CRecessive phenotypes always have two recessive alleles.
DThe phenotype of a homozygote is always dominant.
Mark scheme
11May / June 2019 · Paper 11 · Q38Show mark scheme →
Ain the egg cell: X, in the sperm cell: X, in the zygote: XX
Bin the egg cell: X, in the sperm cell: Y, in the zygote: XY
Cin the egg cell: Y, in the sperm cell: X, in the zygote: XY
Din the egg cell: Y, in the sperm cell: Y, in the zygote: YY
Mark scheme
12May / June 2019 · Paper 12 · Q37Also set in May / June 2019 Paper 11Show mark scheme →
A1 : 1
B1 : 2
C1 : 3
D3 : 1
Mark scheme
13May / June 2019 · Paper 12 · Q38Show mark scheme →
A1 A, 2 B, 3 A, 4 A, 5 B, 6 B
B1 A, 2 B, 3 A, 4 B, 5 AB, 6 O
C1 AB, 2 O, 3 A, 4 A, 5 B, 6 B
D1 AB, 2 O, 3 A, 4 B, 5 AB, 6 O
Mark scheme

