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Physics (AS & A Level) 9702 · Chapter 13

Gravitational fields

Gravitational field strength and field lines, Newton's law of gravitation, circular orbits and geostationary satellites, g = GM/r squared, gravitational potential, and gravitational potential energy.

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13.1 Gravitational field

A gravitational field is a field of force: a region where a mass feels a force. Gravitational field strength at a point is the force per unit mass:

g=Fmg = \frac{F}{m}

The unit is N/kg, which is the same as m/s².

Field lines

Field lines show the direction of the force on a small mass. Around a planet they point radially inwards, and they get further apart with distance, so the field weakens. Near the surface over a small region, the lines are close to parallel and equally spaced, so the field is nearly uniform.

Radial field lines pointing inward to a planet, and parallel equally spaced lines near its surface

Radial field lines pointing inward to a planet, and parallel equally spaced lines near its surface

13.2 Gravitational force between point masses

Newton's law of gravitation

For a point outside a uniform sphere, the mass of the sphere may be treated as a point mass at its centre. Two point masses attract with:

F=Gm1m2r2F = \frac{Gm_1m_2}{r^2}

where G=6.67×10−11G = 6.67 \times 10^{-11} N m² kg⁻² and rr is the distance between their centres. It is an inverse square law, so doubling rr makes the force four times smaller.

Circular orbits

For a satellite in a circular orbit, gravity provides the centripetal force:

GMmr2=mv2r\frac{GMm}{r^2} = \frac{mv^2}{r}

which gives v2=GM/rv^2 = GM/r. The satellite's mass cancels, and closer orbits are faster. Using v=2πr/Tv = 2\pi r/T gives:

T2=4π2r3GMT^2 = \frac{4\pi^2 r^3}{GM}

So T2∝r3T^2 \propto r^3. You should be able to derive this, not just quote it.

Geostationary orbits

A geostationary satellite stays above the same point on the Earth's surface. For this, it must:

  • have an orbital period of 24 hours,
  • orbit from west to east, the same direction as the Earth's rotation,
  • be directly above the Equator.

There is only one possible radius, about 4.2×1074.2 \times 10^{7} m from the Earth's centre.

13.3 Gravitational field of a point mass

Put a small mass mm in the field of a point mass MM. Since F=GMm/r2F = GMm/r^2 and g=F/mg = F/m:

g=GMr2g = \frac{GM}{r^2}

Why g is nearly constant near the surface

The Earth's radius is about 6400 km. Rising 1 km changes rr by a tiny fraction, so r2r^2 and therefore gg barely change. This is why we use g=9.81g = 9.81 N/kg and ΔEP=mgΔh\Delta E_P = mg\Delta h for small height changes.

13.4 Gravitational potential

Definition

The gravitational potential at a point is the work done per unit mass in bringing a small test mass from infinity to that point.

ϕ=−GMr\phi = -\frac{GM}{r}

The unit is J/kg.

Potential is a scalar, so potentials from several masses simply add.

Gravitational potential energy

The potential energy of a mass mm at a point is mϕm\phi:

EP=−GMmrE_P = -\frac{GMm}{r}

The change in potential energy between two radii is:

ΔEP=GMm(1r1−1r2)\Delta E_P = GMm\left(\frac{1}{r_1} - \frac{1}{r_2}\right)

where r2>r1r_2 > r_1 for a mass moving outwards, and the potential energy rises.

Field and potential

The field strength is the negative of the potential gradient, g=−Δϕ/Δrg = -\Delta\phi/\Delta r. On a graph of ϕ\phi against rr, the gradient gives the size of gg.

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