Note AcademyNote Academy

Physics (AS & A Level) 9702 · Chapter 25

Astronomy and cosmology

Luminosity and radiant flux intensity, the inverse square law, standard candles, Wien's displacement law, the Stefan-Boltzmann law and estimating a star's radius, redshift, the expanding Universe, Hubble's law and the Big Bang.

5 min read

25.1 Standard candles

Luminosity and radiant flux intensity

Luminosity LL is the total power of radiation emitted by a star, measured in watts.

Radiant flux intensity FF is the radiant power per unit area arriving at an observer, in W/m². This is what we measure.

The inverse square law

The star's power spreads out over a sphere of area 4πd24\pi d^2:

F=L4πd2F = \frac{L}{4\pi d^2}

So doubling the distance gives one quarter of the flux.

Standard candles

A standard candle is an object of known luminosity. Measuring the radiant flux from it, you can work out how far away it is, using d=L/4πFd = \sqrt{L/4\pi F}.

Cepheid variable stars and type Ia supernovae are standard candles. If a standard candle is in a distant galaxy, then its distance gives the galaxy's distance.

25.2 Stellar radii

Wien's displacement law

The hotter a star is, the shorter the wavelength at which it emits most strongly:

λmax∝1T\lambda_{\text{max}} \propto \frac{1}{T}

So λmaxT\lambda_{\text{max}}T is constant, and its value is about 2.9×10−32.9 \times 10^{-3} m K.

Black-body spectra for two temperatures: the hotter curve is higher and peaks at a shorter wavelength

Black-body spectra for two temperatures: the hotter curve is higher and peaks at a shorter wavelength

The Stefan–Boltzmann law

L=4πσr2T4L = 4\pi\sigma r^2T^4

where σ=5.67×10−8\sigma = 5.67 \times 10^{-8} W m⁻² K⁻⁴ and 4πr24\pi r^2 is the star's surface area. Doubling the temperature gives 16 times the power from each square metre.

Estimating a star's radius

  1. Find the star's peak wavelength from its spectrum, and use Wien's law to find its surface temperature.
  2. Find its luminosity from a standard candle or a measured flux and known distance.
  3. Rearrange the Stefan–Boltzmann law: r=L/(4πσT4)r = \sqrt{L/(4\pi\sigma T^4)}.

25.3 Hubble's law and the Big Bang theory

Redshift

The lines in the emission and absorption spectra of distant objects show an increase in wavelength from their known values. This is redshift, and it means they are moving away from us. For speeds much less than the speed of light:

Δλλ≈Δff≈vc\frac{\Delta\lambda}{\lambda} \approx \frac{\Delta f}{f} \approx \frac{v}{c}

The expanding Universe

Almost every distant galaxy shows redshift, and more distant galaxies show more of it. So galaxies are moving away from us and from each other, and the further they are, the faster they are receding. This leads to the idea that the Universe is expanding.

Hubble's law

v≈H0dv \approx H_0 d

The recession speed of a galaxy is approximately proportional to its distance, where H0H_0 is the Hubble constant. Only SI units (s⁻¹) are used.

A graph of recession speed against distance for galaxies: a straight line through the origin with gradient equal to the Hubble constant

A graph of recession speed against distance for galaxies: a straight line through the origin with gradient equal to the Hubble constant

The Big Bang

If the galaxies are moving apart now, then they were closer in the past. Running the expansion backwards, the whole Universe began from an extremely small, hot, dense state and has been expanding ever since. That is the Big Bang theory.

Since v=H0dv = H_0d, the time for a galaxy to reach distance dd at its current speed is d/v=1/H0d/v = 1/H_0, which estimates the age of the Universe. With H0=2.3×10−18H_0 = 2.3 \times 10^{-18} s⁻¹, it gives about 4.3×10174.3 \times 10^{17} s, or 14 billion years.

Test yourself15 flashcards on this chapter.Flashcards →

Practise this chapter

Every past-paper question on these topics, with the mark scheme.