Physics (AS & A Level) · Oct / Nov 2024 · Paper 11 · Question 37
A potentiometer circuit is used to determine the electromotive force (e.m.f.) E of a cell. The circuit includes a second cell of e.m.f. 1.5 V and internal resistance 0.50 Ω that is connected to a uniform resistance wire XY, as shown. The resistance wire XY has a length of 0.96 m and a resistance of 0.50 Ω. The movable connection Z is moved along wire XY. The galvanometer reading is zero when length XZ is 0.64 m. What is the value of e.m.f. E?
- A0.50 V
- B0.75 V
- C1.0 V
- D1.1 V
As printed in the paper
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Correct answer: A. 0.50 V
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