Physics (AS & A Level) · Feb / March 2021 · Paper 12 · Question 7
A cannon fires a cannonball with an initial speed $v$ at an angle $\alpha$ to the horizontal. [diagram of projectile trajectory with maximum height $H$] Which equation is correct for the maximum height $H$ reached?
- A$H = \dfrac{v\sin\alpha}{2g}$
- B$H = \dfrac{g\sin\alpha}{2v}$
- C$H = \dfrac{(v\sin\alpha)^2}{2g}$
- D$H = \dfrac{g^2\sin\alpha}{2v}$
As printed in the paper
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Correct answer: C. $H = \dfrac{(v\sin\alpha)^2}{2g}$
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