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Physics (AS & A Level) · May / June 2019 · Paper 11 · Question 3

9702Scalars and vectors

A particle has velocity V at an angle θ to the horizontal. The components of the particle's velocity are Vv upwards in the vertical direction and Vh to the right in the horizontal direction, as shown. What are expressions for the magnitude of V and for the angle θ?

  1. Amagnitude of V: √(Vv² + Vh²), θ: tan⁻¹(Vh/Vv)
  2. Bmagnitude of V: √(Vv² + Vh²), θ: tan⁻¹(Vv/Vh)
  3. Cmagnitude of V: √(Vv² − Vh²), θ: tan⁻¹(Vh/Vv)
  4. Dmagnitude of V: √(Vv² − Vh²), θ: tan⁻¹(Vv/Vh)

As printed in the paper

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Correct answer: B. magnitude of V: √(Vv² + Vh²), θ: tan⁻¹(Vv/Vh)

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