Physics (AS & A Level) · May / June 2018 · Paper 42 · Question 2
9702
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2(a)[1]
2(b)(i)[1]
2(b)(ii)[1]
2(c)(i)[4]
1. pV = NkT 4.7 × 10–2 × 2.6 × 105 = N × 1.38 × 10–23 × 446 or pV = nRT and N = nNA 4.7 × 10–2 × 2.6 × 105 = n × 8.31 × 446 n = 3.3 (mol) (C1) N = 3.3 × 6.02 × 1023 (C1) N = 2.0 × 1024 2. average increase = 2900 / (2.0 × 1024) = 1.5 × 10–21 J
2(c)(ii)[3]
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