Physics (AS & A Level) · May / June 2018 · Paper 22 · Question 6
9702
As printed in the paper
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6(a)(i)[1]
6(a)(ii)[1]
6(b)(i)[3]
1. E = I2Rt or E = VIt or E = (V2/ R)t E = 2.52 × 2.0 × 5.0 × 60 or 5.0 × 2.5 × 5.0 × 60 or (5.02 / 2.0) × 5.0 × 60 = 3800 J 2. p.d. = 8.0 – (2.0 × 2.5) = 3.0 V
6(b)(ii)[3]
6(b)(iii)[4]
1. Z has larger radius/diameter/(cross-sectional) area Z has (material of) smaller resistivity/greater conductivity 2. current/I (in battery) increases (P = EI so) power/P (produced by battery) increases
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