Physics (AS & A Level) · May / June 2018 · Paper 12 · Question 4

A student applies a potential difference V of (4.0 ± 0.1) V across a resistor of resistance R of (10.0 ± 0.3) Ω for a time t of (50 ± 1) s. The student calculates the energy E dissipated using the equation below. E = \frac{V^2 t}{R} = \frac{4.0^2 \times 50}{10.0} = 80 J What is the absolute uncertainty in the calculated energy value?

1. A1.5 J
2. B3 J
3. C6 J
4. D8 J

As printed in the paper