Physics (AS & A Level) · Oct / Nov 2016 · Paper 23 · Question 6
9702
As printed in the paper
Show the answer and mark scheme
6(a)[1]
charge forms) other to electrical (from ed) (transform energy or done work [1]
6(b)(i)[4]
1. V = IR or E = IR I = 14 / 6.0 = 2.3 (2.33) A [2]
2. total resistance of parallel resistors = 8.0 Ω current = 14 / (6.0 + 8.0) = 1.0 A [2]
6(b)(ii)[2]
P = EI (allow P = VI) or P = V2 / R or P = I2R change in power = (14 × 2.33) – (14 × 1.0) or (142 / 6.0) – (142 / 14) or (2.332 × 6.0) – (1.02 × 14) = 19 W (18 W if 2.3 A used) [2]
6(c)[2]
I = Anvq ratio = (0.50n / n) × (1.8 A / A) or ratio = 0.50 × 1.8 = 0.90 [2]
Make a free account to save your answers and see your weak topics and ask the AI why a wrong answer is wrong.