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Physics (AS & A Level) · May / June 2016 · Paper 43 · Question 9

9702

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A thin rectangular slice of aluminium has sides of length 65 mm, 50 mm and 0.10 mm, as shown in Fig. 9.1. current direction of magnetic field 3.8 A 0.10 mm 50 mm 65 mm P Q Z Y X R S Fig. 9.1 (not to scale) Some of the corners of the slice are labelled. A current I of 3.8 A is normal to face RSXY of the slice. In aluminium, the number of free electrons per unit volume is 6.0 × 1028 m−3. A uniform magnetic field of magnetic flux density B equal to 0.13 T is normal to face QRYZ of the aluminium slice in the direction from Q to P. A Hall voltage VH is developed across the slice and is given by the expression VH = BI ntq .

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  • 9(a)[1]

    0.10 mm [1]

  • 9(b)[2]

    VH = (0.13 × 3.8) / (6.0 × 1028 × 0.10 × 10–3 × 1.60 × 10–19) = 5.1 × 10–7 V [2]

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