Physics (AS & A Level) · May / June 2016 · Paper 43 · Question 11
9702
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The variation with time t of the sinusoidal current I in a resistor of resistance 450 Ω is shown in Fig. 11.1. 5 0 10 15 20 25 30 1.0 0.5 0 –0.5 –1.0 I / A t / ms Fig. 11.1 Use data from Fig. 11.1 to determine, for the time t = 0 to t = 30 ms,
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11(a)[2]
period = 15 ms frequency (= 1 / T) = 67 Hz [2]
11(b)[1]
zero [1]
11(c)[2]
Ir.m.s. = I0 / √2 = 0.53 A [2]
11(d)[2]
energy = Ir.m.s. 2 × R × t or ½ I0 2 × R × t or power = Ir.m.s. 2 × R and energy = power × t energy = 0.532 × 450 × 30 × 10–3 = 3.8 J [2]
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