Physics (AS & A Level) · May / June 2016 · Paper 22 · Question 6
9702
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Two parallel vertical metal plates are connected to a power supply, as shown in Fig. 6.1. 16 mm + – metal plate metal plate Fig. 6.1 The separation of the plates is 16 mm.
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6(a)[1]
at least six horizontal lines equally spaced and arrow to the right [1]
6(b)[4]
charge used 2e gain in KE = 15 × 1.6 × 10–19 × 103 = 2 × 1.6 × 10–19 × V (p.d.across plates) or F (= W / d) = 15 × 1.6 × 10–19 × 103 / 16 × 10–3 (hence V = 7500 V or F = 1.5 × 10–13 N) E = V / d or E = F / Q E = (7500 / 16 × 10–3) or E = (1.5 × 10–13 / 3.2 × 10–19) E = 4.7 × 105 (468 750) V m–1 [4]
or KE (= ½mv2) = 15 × 103 × 1.6 × 10–19 v = [(2 × 15 × 103 × 1.6 × 10–19) / (6.68 × 10–27)]1/2 = 8.5 × 105 m s–1 (C1) a (= v2 / 2s) = (8.5 × 105) 2 / 2 × 16 × 10–3 = 2.25 × 1013 m s–2 F (= 6.68 × 10–27 × 2.25 × 10–13) = 1.5 × 10–13 N E = F / Q (C1) Q = 2e (C1) E = 4.7 × 105 V m–1 (A1)
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