Physics (AS & A Level) · May / June 2016 · Paper 21 · Question 6
9702
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6(a)[1]
(coulomb is) ampere second [1]
6(b)[3]
(total) charge or Q = nAle I = Q / t and l / t = v I = nAle / t = nAve therefore v = I / nAe [3]
6(c)(i)[3]
ratio = (I / nAYe) / (I / nAZe) = AZ / AY or 4A / A or πd2 / (πd2 / 4) = 4 [3]
6(c)(ii)[2]
R = ρl / A or R = 4ρl / πd2 RY = ρl / A and RZ = ρ(2l) / 4A so RY / RZ = 2 or RY = 4ρl /πd2 and RZ = 4ρ(2l) /π4d2 or 2ρl / πd2 so RY / RZ = 2 [2]
6(c)(iii)[2]
V = 12RY / (RY + RZ) or I = 12 / (RY + RZ) and V = IRY V = 12 × 2/3 = 8(.0) V [2]
6(c)(iv)[1]
ratio = I2RY / I2RZ or (VY 2 / RY) / (VZ 2 / RZ) or (VYI) / (VZI) = 2 [1]
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