Physics (AS & A Level) Paper 52
Feb / March 2016·9702·2 questions
Mock exam: 75 min, official timing
Question paper
Question 1
Question 2
Mark scheme
Question 1
Planning (15 marks) Defining the problem (2 marks) P k is the independent variable and h is the dependent variable, or vary k, measure h. [1]
P Keep mass of object constant. [1]
Methods of data collection (4 marks) M Labelled diagram (minimum two labels) showing object (mass) attached to cord and other end of cord fixed (e.g. stand and clamp or hook) and rule(r) drawn vertically next to cord. [1]
M Method of measuring mass e.g. balance / scales. [1]
M k = (weight or force) / extension or mg / extension;
allow graphical methods. Allow any subject e.g. mg = k × extension. [1]
M Use of rule to measure h or maximum distance / length (fallen by the object). Allow clear indication on diagram (i.e. dotted lines) linking distance h to rule. Do not credit length of cord. [1]
Method of analysis (3 marks) → Plot a graph of ( )
Question 2
2(a)[1]
Gradient = m c P θ ∆ y-intercept = w w m c k P θ ∆ +
2(b)[2]
T1 Column heading mm / g 100 200 300 400 500 600 U1 From ± 10 to ± 60
2(c)(i)[2]
G1 Six points plotted correctly U2 Error bars in mm plotted correctly
2(c)(ii)[2]
G2 Line of best fit G3 Worst acceptable straight line. Steepest or shallowest possible line that passes through all the error bars.
2(c)(iii)[2]
Gradient of the line of best fit; the triangle used should be at least half the length of the drawn line. (1)
Absolute uncertainty: gradient of line of best fit − gradient of worst acceptable line, or ½(steepest worst line gradient − shallowest worst line gradient). (1)
2(c)(iv)[2]
y-intercept of the line of best fit. (1)
Absolute uncertainty: y-intercept of line of best fit − y-intercept of worst acceptable line, or ½(steepest worst line y-intercept − shallowest worst line y-intercept). (1)
2(d)(i)[3]
cm in the range 470 to 530 and given to 2 or 3sf k =y-intercept x P – mwcw∆θ k =y-intercept x 50 – 21000 Units for cm and k
2(d)(ii)[1]
Percentage uncertainty in cm: (Δgradient/gradient + 5/50 + 0.5/20) × 100 = (Δgradient/gradient + 12.5%). (1)