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Physics (AS & A Level) · Feb / March 2016 · Paper 42 · Question 2

9702

As printed in the paper

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  • 2(a)(i)[2]

    sum of kinetic and potential energy of atoms/molecules reference to random (distribution) [2]

  • 2(a)(ii)[1]

    no forces (of attraction or repulsion) between molecules [1]

  • 2(b)[3]

    pV = NkT or pV = nRT and R = kNA , n = N / NA 1/3 Nm<c 2> = NkT or 1/3 m<c 2> = kT <EK> = 1/2 m<c 2> so <EK> = 3/2 kT [3]

  • 2(c)(i)[2]

    <EK> = 3/2 × 1.38 × 10–23 × (273 + 12) = 5.9 (5.90) × 10–21 J [2]

    (use of T = 12 K not T = 285 K scores 0 / 2)

  • 2(c)(ii)[2]

    number = (17 / 32) × 6.02 × 1023 = 3.2 (3.20) × 1023 [2]

  • 2(c)(iii)[1]

    internal energy = 5.9 × 10–21 × 3.2 × 1023 = 1900 (1890) J [1]

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