Physics (AS & A Level) · Feb / March 2016 · Paper 42 · Question 10
9702
As printed in the paper
The question as text
A small coil of wire is situated in a non-uniform magnetic field, as shown in Fig. 10.1. constant velocity coil, 40 turns non-uniform magnetic field x P Fig. 10.1 The coil consists of 40 turns of wire and moves with a constant speed in a straight line. The coil has displacement x from a fixed point P. The variation with x of the magnetic flux Φ in the coil is shown in Fig. 10.2. 4 6 3 5 8 7 2 0 2 4 5 6 x / cm / 10–6 Wb \ 3 1 Fig. 10.2
Read automatically from the paper; the printed page above is exact.
Show the answer and mark scheme
10(a)(i)[1]
change in flux linkage = 40 × (5.0 – 3.0) × 10–6 = 8(.0) × 10–5 Wb [1]
10(a)(ii)[2]
time taken = 8.0 × 10–5 / 5.0 × 10–4 = 0.16 (s) speed = 3.0 × 10–2 / 0.16 = 0.19 (0.188) m s–1 or E = (∆Φ / ∆x) × speed speed = 5.0 × 10–4 / (8.0 ×10–5 / 3.0 ×10–2) (C1) = 0.19 (0.188) m s–1 (A1) [2]
10(b)[2]
a constant non-zero value of E from 0 to 3 cm and a different constant non-zero value of E from 3 to 6 cm E from 3–6 cm has the opposite sign to and larger value than E from 0–3 cm [2]
Make a free account to save your answers and see your weak topics and ask the AI why a wrong answer is wrong.