Physics · Oct / Nov 2018 · Paper 11 · Question 16
The specific heat capacity of lead is 130 J / (kg °C). Lead of mass 0.50 kg is heated from 10 °C to 35 °C. Which calculation gives the amount of thermal energy, in J, absorbed by the lead?
- A0.50 × 130 × 25
- B0.50 × 130 × 35
- C\frac{0.50 \times 130}{25}
- D\frac{0.50 \times 130}{35}
As printed in the paper
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Correct answer: A. 0.50 × 130 × 25
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