Physics · May / June 2023 · Paper 42 · Question 1
0625
As printed in the paper
Show the answer and mark scheme
1(a)(i)[2]
no resultant / net force
no resultant/net moment
1(a)(ii)[2]
4.7 × 107 J or 47 MJ
(∆)Ep = mg(∆)h OR (∆Ep =) mg(∆)h OR (∆Ep =) 3200 × 9.8 × 1500
1(b)(i)[3]
point, labelled 1, on either of the horizontal sections of the graph (to the left of A or to the left of B)
point, labelled 2, on the graph between A and the start of the horizontal section of the graph to the left of B
point, labelled 3, on the graph between the start of the curved section to the right of the origin and the start of the horizontal section of the graph to the left of A
1(b)(ii)[4]
(initially there is acceleration due to) weight OR gravitational force
OR unbalanced force / resultant force / downward force
(then) air resistance increases as speed or velocity increases
(as air resistance increases) resultant force downwards decreases OR acceleration decreases
constant speed when air resistance = weight / gravitational force
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