Physics · May / June 2023 · Paper 41 · Question 1
0625
As printed in the paper
The question as text
Fig. 1.1 shows a straight section of a river where the water is flowing from right to left at a speed of 0.54 m / s. swimmer current P 0.54 m / s river Fig. 1.1 (not to scale) A swimmer starts at point P and swims at a constant speed of 0.72 m / s relative to the water and at right angles to the current.
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1(a)(i)[4]
(magnitude of velocity =) 0.90 m / s
use of Pythagoras’ theorem e.g. a2 + b2 = c2 OR (speed =) (
220.54
0.72
OR
correct vector triangle or rectangle drawn
(direction of velocity =) 53° (to riverbank)
use of trigonometry to find angle e.g. tanθ = 0.72 / 0.54
OR
(only) angle with horizontal identified on the diagram
1(a)(ii)[3]
(distance =) 81 m
v = s / t OR (s =) vt OR (s =) 0.9(0) × 90
(time =) 1.5 × 60 (= 90) OR (time =) 90
1(b)[2]
friction (of water backwards) OR resistance (on swimmer backwards)
(friction / resistance) balances forward force OR (there is) no resultant force
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