Physics · Oct / Nov 2020 · Paper 42 · Question 2
0625
As printed in the paper
Show the answer and mark scheme
2(a)[1]
force × perpendicular distance (from point)
2(b)(i)[1]
0.80 N
2(b)(ii)[2]
(moment = force × distance = ) 0.8 × 0.25
(moment =) 0.20 N m
2(b)(iii)[1]
same value as (ii) with correct unit
2(b)(iv)[2]
F × 0.75 = 0.20 in any form OR (F =) 0.2 / 0.75
(F = 0.2 / 0.75 = ) 0.27 N
2(c)[2]
(perpendicular) distance (from pivot) of F decreases / is less (than 0.75 m)
OR
(perpendicular) distance (from pivot) of
W increases / is more (than 0.75 m)
(so) increased / greater (force F) (needed for greater moment)
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