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Mathematics · Oct / Nov 2025 · Paper 61 · Question 5

YMA01

As printed in the paper

The question as text

5. The weights, x grams, of 300 medium-sized apples are summarised in the table below. Weight Frequency 105  x < 115 28 115  x < 125 42 125  x < 130 75 130  x < 140 63 140  x < 150 52 150  x < 170 40 A histogram is drawn (not shown) to represent these data. The bar that represents the class 125  x < 130 is 1.8 cm wide and 12 cm high.

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  • 5(a)[3]

    Width = 7.2

    Area of 21.6 for a frequency of 75 so 21.6

    75 ×

    40

    =

    11.52

    for

    a frequency of 40 or w × h = 11.52 or fd = 15

    11.52

    2

    =

    ×

    =

    h

    or

    12

    1.6

    7.2

    15

    5

    5.5

    [Q

    =

    130 ]

    +

    ×

    10

    or

    [Q

    =

    130 ]

    +

    ×

    10

    2

    63

    2

    63

  • 5(b)[2]

    x −

    130

    150 145

    −

    or 140

    −

    x

    208 150

    −

    or

    =

    =

    −

    −

    −

    −

    140 130

    208 145

    140 130

    208 145

    = awrt 130.8 or awrt 130.9

    ]6000[

    [

    and [

    ]2 "20" 200

  • 5(c)(i)[2]

    y =

    =

    20]

    w =

    ×

    +

    300

    =

    240

    150000

    [

    ]

  • 5(c)(ii)[3]

    Var( )

    y =

    −

    "20" [ 100]

    2

    =

    300

    [

    ]

    w =

    ×

    =

    Var( )

    4 "100"

    400

    Notes

    (a)

    B1

    7.2 or exact equivalent

    for sight of 11.52 or w × h = 11.52 or fd = 15

    M1

    May be implied by h = 1.6

    A1

    1.6 or exact equivalent

    for any valid method to find the median allow use of n + 1

    (b)

    M1

    allow working backwards [140 – ] 58 10

    or [140 –] 57.5 10

    63×

    A1

    awrt 130.8 allow awrt 130.9 if using (n + 1) No fractions

    for a correct method to find the mean of w

    (c)(i)

    M1

    "72000"

    Alt:

    w =

    6000 2 300 200[ 72000]

    ×+

    ×

    =

    and

    w =

    300

    A1

    cao correct answer is 2/2

    for a correct method to find Var(y)

    (c)(ii)

    M1

    or for

    2

    w =

    17400000

    for a correct method to find Var(w) ft their Var(y)

    ×

    +

    =

    is M0A0

    2 "100" 200

    400

    M1

    17400000

    or for

    w =

    −

    Var( )

    "240"

    2

    300

    A1

    cao answer only with no working shown scores M1M0A0

    SC

    If no marks scored in (ii), allow M1(M0A0) for

    150000

    −

    "20"

    2

    300

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