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Mathematics · Oct / Nov 2025 · Paper 51 · Question 3

YMA01

As printed in the paper

The question as text

3. [In this question i and j are horizontal perpendicular unit vectors.] A particle P of mass 2 kg moves on a smooth horizontal surface under the action of two forces F1 and F2, where F1 = (–2i + 3j) N and F2 = (4i + 2j) N.

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  • 3(a)[3]

    Resultant force

    (

    ) (

    )( )

    = −

    +

    +

    +

    =

    +

    2

    i

    3

    j

    4

    i

    2

    j

    2

    i

    5

    j

    Correct use of

    F

    =

    m

    a

    Acceleration

    )(

    )

    (

    =

    i

    +

    2.5

    j

    ms−

    2

    (

    )

  • 3(b)[4]

    v

    =

    3

    i

    −

    4

    j

    +

    3

    a

    (

    )

    (

    )

    v

    =

    3

    i

    −

    4

    j

    +

    3

    i

    +

    2.5

    j

    Use of Pythagoras

    (

    )

    =

    2

    +

    2

    =

    6.95 ms−

    1

    v

    6

    3.5

  • 3(c)[3]

    Resultant force

    (

    (

    )

    (

    )

    )( )

    =

    2

    +

    b

    i

    +

    5

    +

    c

    j

    N

    Correct use of direction to

    form equation in b and c

    only

    e.g 2

    +

    b

    =

    5

    +

    c

    or 2

    + =

    b

    λ

    and 5

    + =

    c

    λ

    with

    λ eliminated

    b c

    −=

    3

    *

  • 3(d)[4]

    Use magnitude of resultant

    to form an equation in b and

    c

    (

    )

    2

    (

    )

    2

    200

    =

    2

    +

    b

    +

    5

    +

    c

    Form an equation in b or c

    only

    ALT 1:

    Use magnitude of resultant

    to form equation in λ

    =

    λ

    2

    +

    λ

    2

    200

    Use either

    λ

    =

    10 or

    λ

    = −

    10

    to find equations in b and c

    2

    + =

    + =

    b

    10 and 5

    c

    10

    Or 2

    + = −

    + = −

    b

    10 and 5

    c

    10

    (

    )

    F

    =

    8

    i

    +

    5

    j

    N

    3

    (

    )

    = −

    −

    F

    12

    i

    15

    j

    N

    3

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