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Mathematics · Oct / Nov 2025 · Paper 31 · Question 7

YMA01

As printed in the paper

The question as text

7. In this question you must show all stages of your working. Solutions relying entirely on calculator technology are not acceptable. A curve C has equation 2 x k x y 2 x e ( 3 2 ) where k is a constant. Given that C has two distinct turning points, find the range of possible values of k. (7)

Read automatically from the paper; the printed page above is exact.

Show the answer and mark scheme

d

y

(

)

=

2

+

−

+

2

+

−

×

+

−

2e

x

(3

k

2)

x

2 e

x

x

(3

k

2)

x

2

x

(3

k

2)

d

x

2

x

2

+

(3

k

−

2)

x

+ =

1

0

(3

k

−

2)

2

−××

4 2 1

(

)

2

−

−

>

9

k

12

k

4

0

12

±

( 12)

−

2

−××−

4 9 ( 4)

−

−

=

=

=

9

k

2

12

k

4

0

k

k

...

2 9

×

−

+

2

2 2

2

2 2

k

<

or

k

>

3

3

(

)

(

d

y

x

2

+

(3

k

−

2)

x

x

2

+

(3

k

−

2)

x

M1:

Attempts the product rule achieving

=

A

e

+

e

d

x

where f(x) is a quadratic function of x, condone missing/misplaced

brackets for the M.

2 (3

2ex

+

k

−

2)

x

2 (3

(

)

A1:

One of

or

2 e

x

x

+

k

−

2)

x

×

2

x

+

(3

k

−

2)

(unsimplified)

A1:

Correct unsimplified derivative

dM1: Sets their derivative equal to zero (may be implied), collects terms and

attempts

on a 3 term quadratic – must be extracted not just part

b

2

−

4

ac

of the quadratic formula. It is dependent on the previous method mark.

A1:

or equivalent quadratic expression or multiple thereof.

Need not be simplified.

M1:

Must have attempted

and reached a quadratic in k. Attempts to

solve their quadratic in k (including via a calculator) and attempts the

outside region for their critical values (accept with endpoints included.).

Accept with decimals answer correct to 3 s.f. for this mark.

2

−

2 2

2

+

2 2

A1:

<

or

>

or exact equivalent. Allow with “and” instead of

k

k

3

3

“or” when given as two ranges, but use of set notation must use union, not

intersection. E.g.

Alternative method via implicit differentiation scores the same way with

M1A1A1 for correct differentiation. M1 for a correct form of derivative

statement up to constant/sign errors.

NB: method must be seen for the dM mark, if critical values appear from a

derivative statement with no method shown (by calculator) then it is dM0. The

discriminant must be considered. But the last mark is not dependent, so may

be scored for selecting the correct “outside” region for their cvs.

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