Mathematics · May / June 2025 · Paper 21 · Question 1
YMA01
As printed in the paper
Show the answer and mark scheme
1(a)[4]
1
−
4x
7 6 ...
×
7 6 5 ...
××
Correct form for term 3 or term 4: Either
(
)
2
or
(
)
3
o.e.
x
x
2
6
7
×
6
7
××
6 5
(
)
2
or
(
)
3
o.e.
−
4
x
−
4
x
2
6
1 28
336
2
2240
3
= −
x
+
x
−
x
Sets "336" 5 "28"k
1(b)[2]
×−
= 1316
(
) 13
k =
(a) Note that a correct expression scores 4/4
M1: Correct form for
2x or
3x . Look for the correct binomial coefficient with the correct power of x. You do
not need to be concerned with the 4
− which may have been omitted.
Allow alternative equivalent notation for the binomial coefficient for this mark e.g. 7
C or 7
2
or 7!
2!5! etc
Condone invisible brackets for this mark e.g. 7
2 1
5
−
4
2
C
x
A1: Correct
2x or
3x term (which may be unsimplified). They must have a numerical expression or value
for their binomial coefficient for this mark. i.e. do not allow e.g. 7
C
3
Do not condone poor bracketing for this mark but may be implied by further work.
B1: For the series starting 1 28x
−
(terms may be in any order or as a list)
Condone
1
−
28x
1
but not e.g. 1
+−
28x
isw if they subsequently incorrectly attempt to simplify their answer.
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