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Mathematics · Oct / Nov 2024 · Paper 41 · Question 1

YMA01

As printed in the paper

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  • 1(a)[4]

    1

    −

    1

    1

    3

    (

    )

    −

    3

    8

    −

    3

    x

    =

    1

    −

    x

    3

    2

    8

    1

    −

    (

    )

    2

    (

    )(

    )

    3

    3

    3

    −

    1

    −−

    1

    1

    3

    −

    1

    −−

    1

    1

    −−

    1

    2

    3

    3

    (

    )

    1

    −

    x

    = + −

    1

    1

    −

    x

    +

    3

    3

    −

    x

    +

    3

    3

    3

    −

    x

    +

    ...

    8

    3

    8

    2!

    8

    3!

    8

    1

    1

    1

    1

    7

    (

    )

    8

    −

    3

    x

    −

    =

    +

    x

    +

    x

    2

    +

    x

    3

    +

    ...

    3

    2

    16

    64

    1536

  • 1(b)[2]

    2

    3

    1

    1

    2

    1

    2

    7

    2

    2851

    −

    1

    2851

    +

    +

    +

    +

    ...

    =

    3

    6

    =

    =

    ...

    2

    16 3

    64 3

    1536 3

    5184

    5184

    or 2333

    5184

    =

    12851

    2851

    1

    Note a misread of (

    )

    8 3x

    −

    can score a maximum of B1M1A0A0 M0A0

    3

    (a)

    − must be evaluated. May be implied by further work e.g. 1

    1

    1 1 ...

    1

    B1: Obtains (

    )

    .

    ...

    ±

    x

    −

    8

    3

    2 ±

    3

    2

    provided this has not come from an incorrect method.

    1

    1

    1

    1

    1

    e.g. (

    8

    3

    x

    )

    −

    ...

    is B0.

    −

    =

    =

    +

    +

    +

    3

    1

    (

    )

    2

    2

    1

    3

    3

    x

    (

    )

    1

    3

    3

    x

    8

    −

    3

    x

    3

    2

    2

    M1: Attempts the binomial expansion of (1 + kx)n to get the third or fourth term unsimplified with

    an acceptable structure.

    The correct binomial coefficient must be combined with

    2x or

    3x which may be unsimplified.

    (

    )

    (

    )(

    )

    −

    −−

    1 ...

    −

    −−

    1

    −−

    2 ...

    1

    1

    1

    1

    1

    Look for

    3

    3

    x

    2

    or

    3

    3

    3

    x

    3

    o.e. (you do not need to be concerned

    2!

    3!

    3

    with their

    which may be 1 or e.g. if they have a negative sign in front of the whole term)

    −

    8

    1

    1

    −

    −

    Do not allow notation such as

    3

    ,

    3

    unless interpreted correctly in further work.

    1

    2

    May be implied by correct coefficients with

    2x or

    3x

    1

    1

    7

    1x for x for this mark) which

    A1: For 2 correct simplified terms of

    x

    ,

    x

    2

    ,

    x (allow

    3

    16

    64

    1536

    may be listed.

    Condone if coefficients are given as decimals i.e.

    0.0625 , 0.015625

    x

    x

    2

    , 0.004557...

    x

    3

    1

    −

    3

    1

    1

    7

    3

    Also allow for

    1

    −

    x

    = +

    1

    x

    +

    x

    2

    +

    x

    3

    +

    ...

    (Note B0M1A1A0 is possible)

    8

    8

    32

    768

    1

    1

    1

    7

    A1:

    +

    x

    +

    x

    2

    +

    x

    3

    . Isw following a correct answer.

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