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Mathematics · May / June 2024 · Paper 21 · Question 7

YMA01

As printed in the paper

The question as text

7. The circle C1 has equation 2 + y 2 + 8x – 10y = 29 x

Read automatically from the paper; the printed page above is exact.

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  • 7(a)[3]

    x

    y

    x

    y

    Attempts (

    +

    4

    )

    2

    +

    (

    −

    5

    )

    2

    ...

    =

    ...

    x

    y

    Correct centre (

    )

    −

    4, 5

    Exact radius 70

    Attempts distance (or distance 2) from (

    ''

    −

    4, 5 ''

    )

    to (

    '' 5,

    −

    8 ''

    )

  • 7(b)[3]

    to (

    )

    2

    2

    Full method. E.g. compares

    9

    +

    13

    70

    +

    52

    States that

    distance between centres

    =

    250

    =

    15.81

    sum of radii = 70

    +

    52

    =

    15.58

    Concludes as sum of radii < distance between centres, result proven *

    (a)

    Attempts to complete the square for both variables. Look for (

    ) (

    M1:

    ±

    4

    2

    ,

    ±

    x

    y

    or may be implied by (

    )

    by inspection from the equation.

    ±

    4,

    ±

    5

    (

    )

    A1:

    −

    4, 5

    A1:

    70 which may be scored following (

    )

    (

    )

    x

    ±

    4

    2

    +

    y

    ±

    5

    2

    =

    70

    (b)

    Attempts distance (or distance 2) from (

    )

    to (

    )

    M1:

    ''

    −

    4, 5 ''

    '' 5,

    −

    8 ''

    (condone sign errors)

    to their (

    )

    2

    2

    dM1: Full method. E.g. compares their

    9

    +

    13

    '' 70 ''

    +

    52

    A1*: Requires correct calculation(s), correct reason and minimal conclusion. Must be

    evidence to support the inequality – e.g. decimal values – not just the inequality

    stated. May use the difference between sum of radii and distance between centres.

    (b) Alt

    2

    2

    2

    2

    M1:

    Attempts to solve

    x

    +

    y

    +

    8

    x

    −

    10

    y

    =

    29

    and

    x

    +

    y

    −

    10

    x

    +

    16

    y

    = −

    37

    forming a

    linear equation (need not be simplified for this mark)

    FYI: Linear equation is 18

    x

    −

    26

    y

    =

    66

    o.e. if the calculations are correct

    dM1: Attempts to solves their 18

    −

    26

    =

    66

    simultaneously with either circle equation

    x

    y

    reaching a 3 term quadratic for either x or y.

    A1*: Requires

    correct equations
    correct ''solution'' stating no roots and concluding no points of intersection and

    minimal conclusion

    9

    −

    33

    x

    2

    2

    2

    E.g. Substitute

    y

    =

    into

    x

    +

    y

    +

    8

    x

    −

    10

    y

    =

    29

    gives

    250

    x

    −

    412

    x

    13

    2

    and

    ''

    −

    4

    ''

    = −

    308256

    <

    0

    so no solutions

    b

    ac

    FYI the equation in y (if correct) is

    2

    250

    y

    +

    984

    y

    +

    1116

    =

    0

    sin

    sin

    x

    x

    States or uses

    tan

    x

    =

    5sin

    x

    ×

    +

    13

    =

    cos

    x

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