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Mathematics · May / June 2024 · Paper 21 · Question 10

YMA01

As printed in the paper

The question as text

10. In this question you must show all stages of your working. Solutions relying entirely on calculator technology are not acceptable. The number of dormice and the number of voles on an island are being monitored. Initially there are 2000 dormice on the island. A model predicts that the number of dormice will increase by 3% each year, so that the numbers of dormice on the island at the end of each year form a geometric sequence.

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  • 10(a)[2]

    2000 1.03

    ×

    =

    awrt 2390

    3470

    4

    7

    3

    (

    )

    3690

    =

    ,3470

    =

    =

    =

    0.94...

  • 10(b)[3]

    ab

    ab

    b

    3690

    3 3470

    3690

    Hence

    0.9797...

    a =

    dM1

    b =

    =

    3690

    4

    0.9797..

    t

    N =

    4000 0.98

    ×

    T

    1.03

    4000

    T

    T

    Sets

    2000 1.03

    ×

    =

    4000 0.98

    ×

    =

  • 10(c)[3]

    0.98

    2000

    1.03

    log

    log 2

    ...

    T

    =

    T

    =

    0.9

    8

    T

    =

    13.9

    (a)

    5

    6

    M1:

    Attempts

    2000 1.03

    ×

    or

    2000 1.03

    ×

    . May use successive iterations (finding each

    year) but end up at one these in effect.

    A1:

    Awrt 2390

    (b)

    M1:

    Makes progress in using the model and attempting to find one of the variables a or b3

    (or b). Allow if r is used instead of b for the M’s.

    3470

    3

    6

    3

    Allow from the indexing error

    3690

    =

    ,3470

    =

    =

    ab

    ab

    b

    3690

    dM1: Full method to find values for a and b.

    3

    6

    Condone this being scored from

    3690

    =

    ,3470

    =

    ab

    ab

    4000 0.98

    t

    A1:

    N =

    ×

    Accept awrt 4000 to 2sf,, awrt 0.98. Must be seen as an equation not

    just values of a and b but allow if the equation is seen (c) (including the N = ).

    Condone n or T used the variables.

    (c)

    M1:

    Makes progress towards solving the problem by forming a single term with single

    power T. Follow through on their equations provided that they are of the correct form.

    T

    T

    Alternatively takes logs of both sides 2000 1.03

    ×

    =

    4000 0.98

    ×

    and uses addition

    law and power law of logs, e.g ln 2000

    ln1.03

    ln 4000

    ln0.98

    +

    T

    =

    +

    T

    T

    1.03

    4000 1.03

    T

    −

    1

    T

    Award from an attempt on

    2000 1.03

    ×

    =

    4000 0.98

    ×

    =

    0.98

    similar index error.

    dM1: Full and complete attempt to find T. Dependent upon previous method but may be

    implied for the correct value for their

    a

    =

    b

    T

    A1:

    cao

    T =

    13.9

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