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Mathematics · Oct / Nov 2023 · Paper 61 · Question 6

YMA01

As printed in the paper

The question as text

6. The variables x and y have the following regression equations based on the same 12 observations. Regression equation y on x y = 1.4x + 1.5 x on y x = 1.2 + 0.2y

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  • 6(a)[4]

    x

    =

    1.2

    +

    0.2 1.4

    x

    +

    1.5

    o.e or

    y

    =

    +

    y

    +

    o.e

    25

    53

    x

    =

    y

    =

    12

    12

    25

    [

    ]

    (ii)

    =

    ×

    12

    =

    25

    x

    12

    53

    y

    =

    '

    ' 12

    ×

    =

    53

    12

    (

    )

    25 '53'

    ×

    6961

    =

    −

    =

    5.6

    S

    xy

    60

    12

    '5.6'

    '5.6'

    and '5.6'

    S

    S

    0.2

    =

    1.4

    =

    xy

    =

    1.4 and

    xy

    =

    0.2

    '5.6'

    '5.6'

    S

    S

    ×

    S

    S

    xx

    yy

    1.4

    0.2

    xx

    yy

    5.6

    =

    4

    and

    =

    28

    5.6

    S

    S

    r =

    2

    1.4 0.2

    ×

    xx

    yy

    1.4 0.2

    ×

    '5.6'

    r =

    =

    0.5291...

    1.4 0.2

    ×

    =

    0.5291

    '4' '28'

    ×

    awrt 0.529

    Notes

    For either of the two equations o.e or an attempt to solve the two equations simultaneously.

    25

    53

    (a)(i)

    M1

    / 2.08 or better or

    / 4.42 or better

    May be implied by

    x

    =

    y

    =

    12

    12

    25

    53

    For either

    x

    =

    / 2.08 or better or

    y

    =

    / 4.42 or better

    A1

    12

    12

    25

    53

    For both

    x

    =

    / 2.08 or better and

    y

    =

    / 4.42 or better

    (May be written as a coordinate)

    A1

    12

    12

    NB This is M1 on EPEN

    For 25

    (

    12 ×

    12

    14.4

    0.2 1.4

    18

    Allow use of

    x

    rather than x e.g.

    x

    =

    +

    x

    +

    (ii)

    A1*

    As the answer is given no incorrect working must be seen. NB Working must be shown

    53

    ×

    '

    ' 12

    ft their y coordinate.

    For

    12

    (b)

    M1

    (

    )

    Allow use of

    y

    rather than y e.g.

    y

    =

    1.4 14.4

    +

    0.2

    y

    +

    18

    oe

    y =

    53

    A1ft

    For

    or ft their y coordinate × 12 (An answer of exactly 5.6 implies M1A1)

    6961

    25 '

    ×

    '

    y

    M1

    Use of

    =

    −

    ft their

    y

    If

    y

    is not stated then M0 is awarded

    S

    xy

    60

    12

    5.6 (Allow awrt 5.6)

    A1

    For use of the gradient to find

    S

    and

    S

    ft their

    S

    or use of

    S

    xy

    xx

    yy

    xy

    S

    S

    xy

    ×

    xy

    (c)

    1.4

    0.2

    M1

    S

    S

    or setting both

    xy

    and

    xy

    equal to their respective gradients

    S

    S

    xx

    yy

    or (

    )

    2

    S

    S

    =

    4

    and

    =

    28

    or

    xy

    xy

    =

    1.4 0.2

    ×

    S

    S

    A1

    xx

    yy

    S

    ×

    S

    S

    xy

    xx

    yy

    1.4 0.2

    ×

    For a correct expression for r ft their

    S

    ,

    S

    and

    S

    or 1.4 0.2

    ×

    If answer is incorrect then

    xy

    xx

    yy

    M1

    you must see their stated values substituted into a correct expression for r. An answer of

    implies M1A1M1 only

    dA1

    Dependant on all previous marks being awarded. awrt 0.529

    Pearson Education Limited. Registered company number 872828

    with its registered office at 80 Strand, London, WC2R 0RL, United Kingdom

  • 6(b)[4]

    y

    =

    '

    ' 12

    ×

    =

    53

    12

    (

    )

    25 '53'

    ×

    6961

    =

    −

    =

    5.6

    S

    xy

    60

    12

    '5.6'

    '5.6'

    and '5.6'

    S

    S

    0.2

  • 6(c)[4]

    =

    1.4

    =

    xy

    =

    1.4 and

    xy

    =

    0.2

    '5.6'

    '5.6'

    S

    S

    ×

    S

    S

    xx

    yy

    1.4

    0.2

    xx

    yy

    5.6

    =

    4

    and

    =

    28

    5.6

    S

    S

    r =

    2

    1.4 0.2

    ×

    xx

    yy

    1.4 0.2

    ×

    '5.6'

    r =

    =

    0.5291...

    1.4 0.2

    ×

    =

    0.5291

    '4' '28'

    ×

    awrt 0.529

    Notes

    For either of the two equations o.e or an attempt to solve the two equations simultaneously.

    25

    53

    (a)(i)

    M1

    / 2.08 or better or

    / 4.42 or better

    May be implied by

    x

    =

    y

    =

    12

    12

    25

    53

    For either

    x

    =

    / 2.08 or better or

    y

    =

    / 4.42 or better

    A1

    12

    12

    25

    53

    For both

    x

    =

    / 2.08 or better and

    y

    =

    / 4.42 or better

    (May be written as a coordinate)

    A1

    12

    12

    NB This is M1 on EPEN

    For 25

    (

    12 ×

    12

    14.4

    0.2 1.4

    18

    Allow use of

    x

    rather than x e.g.

    x

    =

    +

    x

    +

    (ii)

    A1*

    As the answer is given no incorrect working must be seen. NB Working must be shown

    53

    ×

    '

    ' 12

    ft their y coordinate.

    For

    12

    (b)

    M1

    (

    )

    Allow use of

    y

    rather than y e.g.

    y

    =

    1.4 14.4

    +

    0.2

    y

    +

    18

    oe

    y =

    53

    A1ft

    For

    or ft their y coordinate × 12 (An answer of exactly 5.6 implies M1A1)

    6961

    25 '

    ×

    '

    y

    M1

    Use of

    =

    −

    ft their

    y

    If

    y

    is not stated then M0 is awarded

    S

    xy

    60

    12

    5.6 (Allow awrt 5.6)

    A1

    For use of the gradient to find

    S

    and

    S

    ft their

    S

    or use of

    S

    xy

    xx

    yy

    xy

    S

    S

    xy

    ×

    xy

    (c)

    1.4

    0.2

    M1

    S

    S

    or setting both

    xy

    and

    xy

    equal to their respective gradients

    S

    S

    xx

    yy

    or (

    )

    2

    S

    S

    =

    4

    and

    =

    28

    or

    xy

    xy

    =

    1.4 0.2

    ×

    S

    S

    A1

    xx

    yy

    S

    ×

    S

    S

    xy

    xx

    yy

    1.4 0.2

    ×

    For a correct expression for r ft their

    S

    ,

    S

    and

    S

    or 1.4 0.2

    ×

    If answer is incorrect then

    xy

    xx

    yy

    M1

    you must see their stated values substituted into a correct expression for r. An answer of

    implies M1A1M1 only

    dA1

    Dependant on all previous marks being awarded. awrt 0.529

    Pearson Education Limited. Registered company number 872828

    with its registered office at 80 Strand, London, WC2R 0RL, United Kingdom

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