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Mathematics · Oct / Nov 2023 · Paper 51 · Question 3

YMA01

As printed in the paper

The question as text

3. A hammer is used to hit a tent peg into soft ground. The hammer has mass 1.8 kg and the tent peg has mass 0.2 kg. The hammer and tent peg are both modelled as particles and the impact is modelled as a direct collision. Immediately before the impact, the tent peg is stationary and the hammer is moving vertically downwards with speed 10 m s –1 Immediately after the impact, the hammer and tent peg move together, vertically downwards, with the same speed v m s –1

Read automatically from the paper; the printed page above is exact.

Show the answer and mark scheme
  • 3(a)[2]

    ×

    =

    +

    v = 9 (positive)

  • 3(b)[3]

    For tent peg,

    0.2(

    0)

    I

    = ±

    v

    −

    or

    For hammer,

    1.8(

    10)

    −= ±

    I

    v

    −

    1.8Ns OR 1.8 kgms1 units needed.

  • 3(c)[5]

    0

    =

    9

    2

    +

    2 (0.12)

    a

    OR

    0

    =

    9

    2

    −

    2 (0.12)

    a

    2

    −

    =

    2

    −

    2

    =

    2

    g

    R

    a

    R

    g

    a

    R =

    690 or 695

    N.B. Using u =10 for 9 can score M0A0M1A1A0 max

    Using s = 12, can score M1A0M1A1A0 max

    (9

    +

    0)

    ALT 1

    0.12

    =

    t

    2

    (

    R

    −

    2 )

    g t

    = ×

    2 9

    R =

    690 or 695

    1

    ALT 2

    0.12

    =

    ××

    2 9

    2

    +

    2

    ×

    0.12

    R

    g

    2

    R =

    690 or 695

    Notes for question 3

    (a)

    M1

    Forms CLM equation, condone sign errors and extra g’s and

    any correct cancellation

    cao

    A1

    (b)

    Impulsemomentum equation, dimensionally correct, correct

    M1

    no. of terms. Condone sign errors.

    N.B. M0 if g is included.

    A1 correct unsimplified equation

    A1

    A1 cao must include units.

    A1

    (c)

    Equation formed to find the acceleration. Must be

    M1

    dimensionally correct and have the correct no. of terms.

    A1

    Correct unsimplified equation. Note

    a = −

    337.5

    M1

    Use of F=ma. Must be dimensionally correct and have the

    correct no. of terms.

    A1

    Correct equation, a does not need to be substituted but should

    be consistent with their a from first equation.

    N.B. Use the equation for a to define the positive direction.

    A1

    cao

    ALT 1

    M1

    Equation(s) formed to find the time

    A1

    Correct unsimplified equation. Note

    t =

    2

    =

    0.02666..

    75

    Use of impmom equation. Must be dimensionally correct and

    M1

    have the correct no. of terms.

    A1

    Correct equation, t does not need to be substituted but should

    be consistent with their t from first equation.

    cao

    A1

    ALT 2

    M2

    Use of workenergy equation. Must be dimensionally correct

    and have the correct no. of terms.

    Correct unsimplified equation, 1 each error.

    A2

    A1

    cao

    (5

    −

    8 )

    +

    5(

    −

    λ

    +

    2

    λ

    j (m s1) isw

    )

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