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Mathematics · Oct / Nov 2023 · Paper 41 · Question 1

YMA01

As printed in the paper

Show the answer and mark scheme
  • 1(a)[4]

    2

    −

    1

    5

    x

    8

    −

    2

    (2

    −

    5 )

    x

    =

    1

    −

    or e.g.

    4

    2

    2

    5

    x

    4 1

    −

    2

    2

    3

    (

    2

    ) (

    3

    )

    (

    2

    ) (

    3

    ) (

    4

    )

    1

    5

    x

    −

    ×−

    5

    x

    −

    ×−

    ×−

    5

    x

    (

    )

    = ×

    8

    1

    + −

    2

    ×−

    +

    ×−

    +

    ×−

    ...

    4

    2

    2!

    2

    3!

    2

    8

    75

    2

    3

    =

    2 10

    +

    x

    +

    x

    +

    125

    x

    ...

    2

    (

    2

    5x

    )

    2

    −

    Alt (a) by

    −

    2

    8 (2

    ×

    −

    5 )

    x

    direct

    −×−

    2

    3

    2

    −×−×−

    2

    3

    4

    3

    B1, M1A1

    expansion

    2

    3

    1

    4

    5

    −

    (

    )

    −

    (

    )

    −

    (

    )

    −

    (

    )

    = ×

    8

    2

    ,

    + −

    2 2

    −

    5

    x

    +

    2

    −

    5

    x

    +

    2

    −

    5

    x

    2!

    3!

    8

    75

    2

    3

    =

    2 10

    +

    x

    +

    x

    +

    125

    x

    ...

    (

    )

    2

    2

    2

    −

    5x

  • 1(b)[1]

    2

    x <

    o.e.

    5

    (a)

    1 1 ...

    1

    2

    −

    2

    to obtain e.g. (

    )

    −

    −

    2

    (

    )

    −

    B1: For taking out a factor of

    2 or 4

    −

    2

    from

    (2

    −

    5 )

    x

    ±

    , 2

    1 ...

    ±

    4

    May be implied by a constant term of 2 or by e.g. (

    2 1 ... −

    ) 2

    ±

    The “8” is likely to be present but it is not required for this mark.

    M1: For the form of the binomial expansion (

    )

    1 ax

    +

    −

    2

    Requires the correct structure for either term three or term four. Allow a slip on the sign.

    So allow for either (

    ) (

    ) (

    or (

    ) (

    ) (

    ) (

    −

    2

    ×−

    3

    −

    2

    ×−

    3

    ×−

    4

    ax

    )

    2

    ax

    )

    3

    where a ≠ 1, could be −5 but must

    ±

    ±

    2

    3!

    ax −

    ) 2

    be the “a” in their

    "2" 1

    (

    .

    ±

    Condone missing brackets around the “ax” for this mark.

    x −

    5

    A1: Any unsimplified or simplified but correct form of the binomial expansion for

    1

    −

    2

    Ignore the factor preceding the bracket for this mark and ignore any extra terms if found.

    2

    3

    (

    2

    ) (

    3

    )

    (

    2

    ) (

    3

    ) (

    4

    )

    5

    x

    −

    ×−

    5

    x

    −

    ×−

    ×−

    5

    x

    (

    )

    Score for

    1

    + −

    2

    ×−

    +

    ×−

    +

    ×−

    o.e.

    2

    2!

    2

    3!

    2

    2

    5

    x

    5

    x

    Brackets must be present unless they are implied by later work. Allow

    for

    −

    2

    2

    75

    125

    2

    3

    The simplified form is

    1 5

    +

    x

    +

    x

    +

    x

    +

    ...

    Allow as a list of terms.

    4

    2

    75

    2

    3

    A1: cao

    2 10

    +

    x

    +

    x

    +

    125

    x

    ...

    This must be simplified and allow as a list of terms.

    2

    2 e.g. 37.5 and ignore any extra terms.

    75

    2

    Do not isw and mark the final answer. E.g. Fully correct work leading to

    2 10

    +

    x

    +

    x

    2

    2

    3

    followed by

    loses the final mark.

    =

    4

    +

    20

    x

    +

    75

    x

    +

    250

    x

    ...

    Alternative to (a) by direct expansion

    (2 5 )

    −

    x

    −

    2

    =

    2

    −

    2

    +

    ....

    B1: This is awarded for

    which may be implied by a final answer of 2 + …

    (2

    −

    5 )x

    −

    2

    M1: For the form of the expansion of

    Requires the correct structure for either term three or term four. Allow a slip on the sign.

    So allow for either (

    ) (

    )( ) (

    −

    2

    ×−

    3

    or (

    ) (

    ) (

    ) ( ) (

    −

    2

    ×−

    3

    ×−

    4

    )

    2

    −

    4

    ±

    5

    x

    2

    −

    5

    )

    3

    2

    ±

    5

    x

    2

    3!

    Condone missing brackets around the 5x.

    −

    A1: Any unsimplified or simplified but correct form of the binomial expansion for

    (2

    −

    5 )x

    Ignore the factor preceding the bracket for this mark and ignore any extra terms if found.

    −×−

    2

    3

    2

    −×−×−

    2

    3

    4

    3

    −

    2

    (

    )

    −

    3

    (

    )

    1

    −

    4

    (

    )

    −

    5

    (

    )

    Score for

    2

    + −

    2 2

    −

    5

    x

    +

    2

    −

    5

    x

    +

    2

    −

    5

    x

    o.e.

    2!

    3!

    Brackets must be present unless they are implied by later work.

    1

    5

    75

    125

    The simplified form is

    2

    3

    Allow as a list of terms.

    +

    x

    +

    x

    +

    x

    +

    ...

    4

    4

    16

    8

    75

    2

    3

    A1: cao

    2 10

    +

    x

    +

    x

    +

    125

    x

    ...

    This must be simplified and allow as a list of terms.

    2

    Allow equivalents for 75

    2 e.g. 37.5 and ignore any extra terms.

    75

    2

    Do not isw and mark the final answer. E.g. Fully correct work leading to

    2 10

    +

    x

    +

    x

    2

    2

    3

    followed by

    =

    4

    +

    20

    x

    +

    75

    x

    +

    250

    x

    ...

    loses the final mark.

    Note: Correct or partially correct answers with no working in (a) should be sent to review.

    (b)

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