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Mathematics · Oct / Nov 2023 · Paper 11 · Question 11

YMA01

As printed in the paper

The question as text

11. y (–1, 28) C l R O x P Figure 5 Figure 5 shows part of the curve C with equation y = f(x) where 2 x x x f ( ) 2 12 14

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  • 11(a)[3]

    2(

    ...)

    2

    x±

    ...(

    x ±

    3) ...

    2

    2(

    x −

    3)

    2

    −

    4

  • 11(b)[1]

    (3,

    −

    4)

  • 11(c)[3]

    28

    4 (

    −−

    =

    = −

    8)

    m

    −−

    1 3

    −

    28

    = −

    8(

    +

    1)

    y

    x

    y

    = −

    8

    x

    +

    20

  • 11(d)[3]

    y

    2

    x

    2

    −

    12

    x

    +

    14

    y

    "2(

    x −

    3)

    2

    −

    4"

    )

    y

    " 8

    −

    x

    +

    20"

    and

    (or

    y

    2

    x

    2

    −

    12

    x

    +

    14

    y

    −

    8

    x

    +

    20

    y

    0,

    x

    0

    Note: answers may appear next to questions or on the diagram.

    If there is a contradiction between the answer by the question/on the diagram and the main

    body of the work then the answer in the main body of the work takes precedence.

    (a)

    2

    B1:

    a = which may be stated or seen in the expression

    2

    2(

    x±

    ...)

    .

    12

    ...(

    x ±

    3) ...

    2

    ...

    ±

    M1:

    may be implied by

    b = ±. Accept unsimplified versions e.g.

    3

    x

    4

    2(

    x −

    3)

    2

    −

    4

    A1:

    isw following a correct expression (e.g. if they proceed to state incorrect

    values for a, b and/or c). If they just state the values then withhold this mark. Constants must

    be integers.

    SC110 2(

    (slip writing missing the squared on the bracket)

    x −

    3)

    −

    4

    (b)

    B1ft:

    (3,

    −

    4)

    or e.g.

    x

    =

    3,

    y

    = −. Condone invisible brackets. Follow through from their part (a)

    4

    so score for (

    −

    , )

    b c

    (c)

    M1:

    Attempts to find the gradient between their minimum point and ( 1, 28)

    −

    . Score for the

    expression 28

    " 4"

    −−

    or equivalent. They must be subtracting the correct way round. Do

    −−

    1 "3"

    not condone sign slips for this mark. If a value appears with no method (nor implied using

    their minimum point and ( 1, 28)

    ), then this mark cannot be scored (M0dM0A0)

    −

    May be part of the equation for l e.g. 28

    −−

    " 4"

    −−

    1 "3"

    or 28

    −−

    " 4"

    −−

    1 "3"

    =

    =

    −

    28

    +

    1

    +

    4

    −

    3

    y

    x

    y

    x

    dM1: Attempts to find the equation using their gradient. |It is dependent on the previous method

    mark. Score for

    −

    28

    = −

    " 8"(

    +

    1)

    or

    +

    4

    = −

    " 8"(

    −

    3)

    but condone one sign slip

    y

    x

    y

    x

    substituting in the coordinates for x and y.

    If they use y

    =

    mx

    + they must proceed as far as

    c

    ...

    .

    c =

    A1:

    = −

    8

    +

    20

    y

    x

    or <> Ignore use of and/or or equivalent notation for

    (d)

    Allow consistent use of either

    this question.

    Note that

    2

    x

    2

    −

    12

    x

    +

    14

    may be expressed as

    2(

    x −

    3)

    2

    −

    4

    Allow the use of f(x) instead of y but the use of R instead of y is not acceptable.

    B1ft: One of

    " 8

    −

    +

    20"

    follow through on their part (c)

    y

    x

    2

    2

    −

    12

    +

    14

    "2"(

    x−

    "3")

    2

    −

    "4"

    y

    x

    x

    follow through on their part (b) so

    2

    2

    −

    12

    +

    14

    <

    " 8

    −

    +

    20"

    May be part of an inconsistent set of inequalities e.g.

    x

    x

    y

    x

    B1ft: Both

    follow through on their part (c)

    y

    " 8

    −

    x

    +

    20"

    2

    2

    y

    2

    x

    −

    12

    x

    +

    14

    follow through on their part (b) so

    "2"(

    x−

    "3")

    −

    "4"

    2

    2

    12

    14

    " 8

    20"

    May also be seen as

    x

    −

    x

    +

    y

    −

    x

    +

    y

    2

    x

    2

    −

    12

    x

    +

    14

    B1cso:

    y

    −

    8

    x

    +

    20

    y

    0,

    x

    0

    Do not isw for this mark.

    Also accept

    2

    x

    2

    −

    12

    x

    +

    14

    y

    −

    8

    x

    +

    20

    y

    0,

    x

    0

    5

    Accept inequalities

    0

    provided

    x

    p

    p

    2

    0

    provided

    20

    y

    q

    q

    Note: The equations may be written in alternative forms e.g. 8

    +

    20

    which is also acceptable

    x

    y

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