Note AcademyNote Academy

Mathematics · May / June 2023 · Paper 61 · Question 1

YMA01

As printed in the paper

The question as text

1. The histogram shows the distances, in km, that 274 people travel to work. Frequency density 0 0 10 20 30 40 50 60 Distance travelled in km Given that 60 of these people travel between 10 km and 20 km to work, estimate

Read automatically from the paper; the printed page above is exact.

Show the answer and mark scheme
  • 1(a)[3]

    eg 1 person = 0.025 large squares/0.6 medium squares/2.5 small squares or

    eg [1 small square =] 0.4 people/[1 medium square =] 10 people/[1 large square =] 40 people

    eg a correct f.d. eg 60/(20 – 10) [= 6]

    eg a correct frequency, 100, 70, 20, 24 associated with the appropriate bar

    eg 8

    or 15

    or 40

    or 30

    10 ×

    20

    30 ×

    24

    or 8 2

    ×

    or 0.8 15

    ×

    2.5 or 8 5 0.4

    ××

    2.5

    2 15 0.4

    ×

    ×

    or 16 or 12 or 70 0.4

    ×

    28 people

  • 1(b)[2]

    5

    5

    Median

    =

    [5]

    +

    ×

    37

    [10]

    −

    ×

    33

    or

    70

    70

    = 7.642... awrt 7.64

  • 1(c)[3]

    [

    ]

    midpoint

    ×

    freq

    =

    2.5 100

    ×

    +

    7.5 70

    ×

    +

    15 60

    ×

    +

    25

    ×

    20

    +

    45

    ×

    24

    =

    3255

    "3255"

    Mean

    =

    274

    = 11.879… awrt 11.9

    Notes

    (a)

    B1: for finding a ratio between people and area. Allow just the numbers for 1 person or for 1 square ie

    0.025, 0.6, 2.5, 0.4, 1.66 or 40 or

    calculating f.d. for any bar correctly, fd = 20, 14, 6, 2 or 0.8

    Information may be seen on diagram. Must be clear it is a fd either by correct use, seen on axes

    associated with correct bar or stated as an fd. May be implied by M1

    M1: for a correct method to find the number of people between 22 and 30 km or 30 and 45 km or

    between 22 and 45 km

    A1: 28

    NB An answer of 28 gains 3/3 unless from obvious incorrect working

    (b)

    5

    −

    137 100

    −

    33

    −

    170 137

    −

    Q

    n

    n

    Q

    n +

    ×

    37

    M1: Allow equivalent for

    or

    2

    =

    or

    n −

    ×or

    5

    2

    =

    70

    5

    170 100

    70

    5

    170 100

    −

    −

    −

    5

    137

    −

    170

    Q

    Allow alternative methods eg

    2

    =

    10

    170 137

    −

    Q

    −

    2

    Allow 37.5 for 37, 137.5 for 137, 32.5 for 33

    A1: awrt 7.64 or 107

    or allow awrt 7.68 or 215

    28 if using n + 1 Allow awrt 7640 m or 7680 m but must

    14

    have units.

    (c)

    M1: Attempt at correct expression for

    midpoint

    ×

    freq

    at least 3 products with correct midpoints

    added with at least 1 of these products fully correct . Allow for 3255

    M1: dep on M1 being awarded for dividing “their sum” by 274

    A1: awrt 11.9 or 3255

    274

    Allow awrt 11900 m but must have units

Make a free account to save your answers and see your weak topics and ask the AI why a wrong answer is wrong.