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Mathematics · May / June 2023 · Paper 51 · Question 7

YMA01

As printed in the paper

The question as text

7. α Figure 4 A car of mass 1200 kg is towing a trailer of mass 600 kg up a straight road, as shown in Figure 4. The road is inclined at an angle α to the horizontal, where sin α = 1 12 The driving force produced by the engine of the car is 3000 N. –2 The car moves with acceleration 0.75 m s The non-gravitational resistance to motion of the car is modelled as a constant force of magnitude 2R newtons • the trailer is modelled as a constant force of magnitude R newtons • The car and the trailer are modelled as particles. The tow bar between the car and trailer is modelled as a light rod that is parallel to the direction of motion. Using the model,

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  • 7(a)[4]

    3000 1200 sin

    g

    600 sin

    g

    2

    R

    R

    1800 0.75

    −

    α

    −

    α

    −

    −

    =

    From exact working

    R =

    60 *

    (

    )

    T

    −

    600 sin

    g

    α

    −

    60

    =

    600 0.75

    Trailer:

  • 7(b)[3]

    OR

    (

    )

    (

    )

    3000 1200 sin

    −

    g

    α

    −

    2 60

    −

    T

    =

    1200 0.75

    Car:

    (T could be replaced by ( T

    −

    ) in either equation, leading to

    T = 1000

    −

    , so tension is 1000 )

    T =

    1000(N)

    Equation of motion

  • 7(c)[4]

    −

    60

    −

    600 sin

    g

    α

    =

    600

    a

    (or – 600a)

    11

    a

    = −

    = −

    0.9166

    12

    11

    0

    =

    12

    2

    +

    2

    −

    12 d

    d =

    78.5 , 79 (m)

    Notes for question 7

    (a)

    Equation of motion for the whole system (or for car AND trailer with T eliminated) to give

    an equation in R only.

    M1

    sinαdoes not need to be substituted

    Correct number of terms, forces resolved where appropriate, condone sign errors and

    sin/cos confusion.

    A1

    Correct equation with at most one error.

    sinαdoes not need to be substituted

    A1

    Correct equation.

    sinαdoes not need to be substituted

    A1*

    Reach the GIVEN answer with at least one intermediate line of working and must come

    from exact working.

    (b)

    Equation of motion for the trailer or for the car. Correct number of terms, forces resolved

    where appropriate, condone sign errors and sin/cos confusion.

    M1

    sinαdoes not need to be substituted but R = 60 does

    A1

    Correct unsimplified equation.

    sinαdoes not need to be substituted

    A1

    Correct answer for T

    (c)

    Form an equation of motion for the trailer to find the new acceleration. Correct number of

    terms, forces resolved where appropriate, condone sign errors and sin/cos confusion.

    M1

    sinαdoes not need to be substituted but R = 60 does

    A1

    Correct unsimplified equation.

    sinαdoes not need to be substituted

    M1

    Complete method, with a calculated acceleration that is not g, to find the distance travelled.

    A1

    Cao 2 or 3sf Must be positive.

    N.B. Allow a negative value of d and made positive for the distance.

    Allow working in column vectors and penalise answers to (a) and (b)

    in column vector form ONCE at the first time it occurs.

    (

    )

    (

    )

    9

    i

    +

    23

    j

    −−

    2

    i

    +

    j

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