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Mathematics · Oct / Nov 2022 · Paper 51 · Question 7

YMA01

As printed in the paper

The question as text

7. Q (m) P (m) Figure 4 A particle P of mass m is attached to one end of a light inextensible string. Another particle Q, also of mass m, is attached to the other end of the string. The string passes over a small smooth pulley which is fixed at the edge of a rough horizontal table. Particle Q is held at rest on the table and particle P hangs vertically below the pulley with the string taut, as shown in Figure 4. The pulley, P and Q all lie in the same vertical plane. The coefficient of friction between Q and the table is μ, where μ < 1 Particle Q is released from rest. The tension in the string before Q hits the pulley is kmg, where k is a constant.

Read automatically from the paper; the printed page above is exact.

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  • 7(a)[7]

    F

    mg

    For P: mg

    −

    kmg

    =

    ma

    Allow mg

    −

    T

    =

    ma

    For Q: kmg

    −

    F

    =

    ma

    Allow T

    −

    =

    F

    ma

    2

    Either of these may be replaced by :

    mg

    −

    F

    =

    ma

    (whole system)

    Produce an equation in k and μonly using T = kmg

    1 (1

    )

    k

    =

    +

    μ

    2

    Attempt to find the acceleration.

    1

  • 7(b)[4]

    [Note that some possible correct forms are:

    a

    =

    g

    (1

    −

    μ

    )

    or (1

    g

    −

    k

    )

    2

    or (

    g k

    −

    μ

    )

    ]

    1

    1

    =

    ×

    (1

    −

    μ

    )

    2

    d

    g

    t

    2

    2

    4

    d

    t

    =

    g

    (1

    −

    μ

    )

    P or Q (or the system) would not move

  • 7(c)[2]

    Accept any of T = mg, T

    >

    ,T

    ≥

    , a = 0, a < 0,

    0

    mg

    mg

    a ≤

    F = T, F > T, F ≥ T , F > mg. Allow F replaced by

    μ

    R

    N.B. Forces referred to must be clearly defined so

    e.g. use of vague terms like ‘forward force’ , ‘opposite force’, ‘force to

    the left or right’ is B0.

    Notes for question 7

    B1 for F

    =

    μ

    mg

    seen e.g. on a diagram

    7(a)

    M1 Equation of motion for P with correct no. of terms, condone sign

    errors

    A1 Correct equation (allow a)

    M1 Equation of motion for Q with correct no. of terms, condone sign

    errors

    A1 Correct equation (allow a)

    N.B. (a) must be used in both equations

    M1 for producing an equation in k and μonly

    A1 oe Must appear in (a)

    M1 Attempt to find the acceleration in terms of g and μ or g and k or g,

    7(b)

    k and μ

    M1 Complete method to find an equation in d, g, t and μonly, condone a

    sign error.

    A1 Correct equation in d, g, t and μonly

    A1 Any equivalent form

    B1 Correct statement. B0 if incorrect extras.

    7(c)

    DB1 Correct reason

    Allow column vectors throughout

    2

    2

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